Update 100+ Python challenging programming exercises.txt

FizzBuzz is a very common interview question, however, it is not difficult and could be solved by a beginner learner.

Author: Rohit-beep-droid

100+ Python challenging programming exercises.txt

@@ -2371,6 +2371,7 @@ solutions=solve(numheads,numlegs)
 print solutions
 
 #----------------------------------------#
+Level: Easy
 Question:
 Write a Person class with an instance variable, age, and a constructor that takes an integer, initialAge, as a parameter. The constructor must assign initialAge to age after confirming the argument passed as initialAge is not negative; if a negative argument is passed as initialAge, the constructor should set age to 0 and print Age is not valid, setting age to 0. In addition, you must write the following instance methods:
 
@@ -2412,5 +2413,29 @@ for i in range(0, t):
     p.amIOld()
     print("")
 #----------------------------------------#
+Level: Easy
+Question:
+Suppose we have a number n. We have to display a string representation of all numbers from 1 to n, but there are some constraints.
+
+1. If the number is divisible by 3, write "Fizz" instead of the number
+2. If the number is divisible by 5, write "Buzz" instead of the number
+3. If the number is divisible by 3 and 5 both, write "FizzBuzz" instead of the number
 
+(Credit: Common interview question)
 
+Hints: Use if-elif-else statements to split the problem into sections.
+
+Answer:
+
+def fizzbuzz(n):
+    for a in range(1,n+1):
+        if a % 3 == 0 and a % 5 == 0:
+            print('FizzBuzz')
+        elif a % 3 == 0:
+            print('Fizz')
+        elif a % 5 == 0:
+            print('Buzz')
+        else:
+            print(a)
+fizzbuzz(n)
+#----------------------------------------#