🌐 Mailman 3 June 2022 - Python-list - python.org

>>> %matplotlib inline results in SyntaxError: invalid syntax
by Mike S Dec. 25, 2023

Dec. 25, 2023

I have installed Python 3.4.4 on XPSP3 and am trying to work my way through this tutorial. A Complete Tutorial on Ridge and Lasso Regression in Python http://www.analyticsvidhya.com/blog/2016/01/complete-tutorial-ridge-lasso-r… In Step 2 "Why Penalize the Magnitude of Coefficients?" we are shown this code: #Importing libraries. The same will be used throughout the article. import numpy as np import pandas as pd import random import matplotlib.pyplot as plt %matplotlib inline I get an error on the last line. I am running this code in Idle Python 3.4.4 Shell... Python 3.4.4 (v3.4.4:737efcadf5a6, Dec 20 2015, 19:28:18) [MSC v.1600 32 bit (Intel)] on win32 Type "copyright", "credits" or "license()" for more information. >>> import numpy as np >>> import pandas as pd >>> import random >>> import matplotlib.pyplot as plt >>> %matplotlib inline SyntaxError: invalid syntax What am I doing wrong? Suggested reading? TIA, Mike

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Re: How to add CC and BCC while sending mails using python
by akegb3＠gmail.com June 20, 2023

June 20, 2023

On Tuesday, September 30, 2008 8:00:16 AM UTC-8, Bernhard Walle wrote: > Hi, > > * cindy jones [2008-09-30 19:57]: > > > > Can someone tel me how to add cc's and bcc's while sending mails using > > python > > Following (tested) snippet should help: > > ------------------ 8< ------------------------------ > from smtplib import SMTP > from email.mime.image import MIMEImage > from email.mime.text import MIMEText > from email.mime.multipart import MIMEMultipart > > to = 'to_address(a)example.invalid' > cc = 'cc_address(a)example.invalid' > bcc = 'bcc_address(a)example.invalid' > > msg = MIMEMultipart() > msg['To'] = to > msg['Cc'] = cc > msg['From'] = 'bernhard(a)bwalle.de' > msg['Subject'] = 'Test' > text = MIMEText('Das ist ein Test') > text.add_header("Content-Disposition", "inline") > msg.attach(text) > > s = SMTP('test.smtp.relay') > s.sendmail(msg['From'], [to, cc, bcc], msg.as_string()) > s.quit() > ------------------ >8 ------------------------------ > > > Regards, > Bernhard Hello Bernhard, I've tried the above code and the bcc address does not receive the message, on the To & CC addresses receive it. Here are snippets from my code, perhaps something will stand out to you? to = 'ed(a)domain.gov' cc = 'ed(a)gmailmail.com' bcc = 'ed(a)home.net' msg = MIMEMultipart() msg['To'] = to msg['Cc'] = cc msg['Subject'] = 'My Subject text here' msg['From'] = 'edsboss(a)domain.gov' smtp = SMTP("smtpserver") smtp.ehlo() smtp.sendmail(msg['From'], [to, cc, bcc], msg.as_string()) Thanks in advance..hope you're still out there!! ~Ed

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When should I use "parent=None" in __ini__ and "parent" in super()
by Mohsen Owzar Sept. 2, 2022

Sept. 2, 2022

Hi Guys I'm writing since almost one-year codes in Python, using TKinter and PyQt5. I'm somehow able to writes GUIs in both of them. But since I'm using more Pyqt5 and using classes with initialization and super() constructs, and also I saw lots of videos and examples of coding them, I still don’t know exactly how and when should I use the parent in __init()__ and super() construct. For example, the following lines use "parent=None" in the __init__ construct and "parent" in the super() construct. And sometimes I do not see any of them in these two constructs. :::::::::::::::::::::::::::::::::::::::::::::::: class MyClass1(QWidget): def __init__(self, name, parent=None): super(MyClass1, self).__init__(parent) print(self.parent().test) :::::::::::::::::::::::::::::::::::::::::::::::: And sometimes without "parent" like the following: :::::::::::::::::::::::::::::::::::::::::::::::: class MyClass2(QWidget): def __init__(self, name): super(MyClass2, self).__init__() print(self.parent().test) :::::::::::::::::::::::::::::::::::::::::::::::: Could anyone explain this to me when and for which action I have to use the first one "MyClass1" and when the second one "MyClass2"? Regards Mohsen

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Byte arrays and DLLs
by Rob Cliffe July 3, 2022

July 3, 2022

I have an application in which I wanted a fixed-length "array of bytes" (that's intended as an informal term) where I could read and write individual bytes and slices, and also pass the array to a DLL (one I wrote in C) which expects an "unsigned char *" parameter. I am using ctypes to talk to the DLL but am open to alternatives. Speed is important. My OS is Windows 10. I started off using a bytearray object (bytes does not support item assignment), but I couldn't find any way of passing it to the DLL directly. Instead I had to convert it to a different type before passing it, e.g. bytes(MyArray) or (ctypes.c_char * LEN).from_buffer(MyArray)) # LEN is the length of MyArray, knownin advance but this was slow, I think because the array data is being copied to a separate object. Eventually after consulting Googol I came up with using a memoryview: MyArray = memoryview(bytearray( <required-length> )) # can read and write to this and passing it to the DLL as MyArray.tobytes() and was gratified to see a modest speed improvement. (I don't know for sure if it is still copying the array data, though I would guess not.) Is this a sensible approach, or am I still missing something? AKAIK it is not possible to give ctypes a bytearray object and persuade it to give you a pointer to the actual array data, suitable for passing to a DLL. Is this (a) false (b) for historical reasons (c) for some other good reason? TIA Rob Cliffe

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Creating lambdas inside generator expression
by Johannes Bauer June 30, 2022

June 30, 2022

Hi list, I've just encounted something that I found extremely unintuitive and would like your feedback. This bit me *hard*, causing me to question my sanity for a moment. Consider this minimal example code (Py 3.10.4 on Linux x64): class Msg(): def hascode(self, value): print("Check for", value) return False conds = [ lambda msg: msg.hascode("foo"), lambda msg: msg.hascode("bar"), ] msg = Msg() print(conds[0](msg)) print(conds[1](msg)) It works perfectly and does exactly what it looks like. The output is: Check for foo False Check for bar False But now consider what happens when we create the lambdas inside a list comprehension (in my original I used a generator expresison, but the result is the same). Can you guess what happens when we create conds like this? conds = [ lambda msg: msg.hascode(z) for z in ("foo", "bar") ] I certainly could not. Here's what it outputs: Check for bar False Check for bar False I.e., the iteration variable "z" somehow gets bound inside the lambda not by its value, but by its reference. All checks therefore refence only the last variable. This totally blew my mind. I can understand why it's happening, but is this the behavior we would expect? And how can I create lambdas inside a generator expression and tell the expression to use the *value* and not pass the "z" variable by reference? Cheers, Joe

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Re: WHAT THE ERROR ON MY CODE???
by De ongekruisigde June 29, 2022

June 29, 2022

On 2022-06-28, Chris Angelico <rosuav(a)gmail.com> wrote: > ‪On Wed, 29 Jun 2022 at 01:37, ‫נתי שטרן‬‎ <nsh531(a)gmail.com> wrote:‬ >> headers["Authorization"] = "Basic >> YjMwMzcwODY3NTUzNDMwNTg5NzA2MjkyNDFmMDE1YWY6VjNKYTk2Y1F4RTFzeTdYbzRnbkt0a2k1djhscXUyU01oSE5VWUwwRg==" >> > > The error is that you just revealed your credentials to the whole > world. This is a public mailing list. > > In fact, you just revealed your credentials to TWO mailing lists at once. I think the term 'script kiddie' applies here. > Good job. > > ChrisA -- Without followers, evil cannot spread. [Spock, "And The Children Shall Lead", stardate 5029.5]

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Re: REPL with multiple function definitions
by Jon Ribbens June 29, 2022

June 29, 2022

On 2022-06-26, Rob Cliffe <rob.cliffe(a)btinternet.com> wrote: > This 2-line program > > def f(): pass > def g(): pass > > runs silently (no Exception). But: > > 23:07:02 c:\>python > Python 3.8.3 (tags/v3.8.3:6f8c832, May 13 2020, 22:20:19) [MSC v.1925 32 > bit (Intel)] on win32 > Type "help", "copyright", "credits" or "license" for more information. > >>> def f(): pass > ... def g(): pass > File "<stdin>", line 2 > def g(): pass > ^ > SyntaxError: invalid syntax > >>> > > Is there a good reason for this? For some reason, the REPL can't cope with one-line blocks like that. If you put a blank line after each one-block line then it will work.

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WHAT THE ERROR ON MY CODE???
by נתי שטרן June 28, 2022

June 28, 2022

import requests from requests.structures import CaseInsensitiveDict url = "https://api.crowdstrike.com/oauth2/token" headers = CaseInsensitiveDict() headers["Content-Type"] = "application/x-www-form-urlencoded" headers["Authorization"] = "Basic YjMwMzcwODY3NTUzNDMwNTg5NzA2MjkyNDFmMDE1YWY6VjNKYTk2Y1F4RTFzeTdYbzRnbkt0a2k1djhscXUyU01oSE5VWUwwRg==" data = "POST" resp = requests.post(url, headers=headers, data=data) print(resp.text) print(resp.status_code) import requests from requests.structures import CaseInsensitiveDict MYurl = " https://api.crowdstrike.com/intel/combined/indicators/v1?q=123.123.123.123" headersa = CaseInsensitiveDict() headersa["Authorization"] = "Bearer "+resp.text resp1 = requests.get(MYurl, headers=headersa) print(resp1.status_code)

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Re: why function throws an error?
by Dennis Lee Bieber June 28, 2022

June 28, 2022

On Tue, 28 Jun 2022 10:57:59 +0300, ??? ???? <nsh531(a)gmail.com> declaimed the following: > def add_route(self, route): > # """ Add a route object, but do not change the :data:`Route.app` > # attribute.""" > self.routes.append(route) > self.router.add(route.rule, route.method, route, name=route.name >) > # if DEBUG: route.prepare() From your subject "why function throws an error?". How would we know? You never show us the error traceback, you never provide a minimal code listing that someone could attempt to run to perform debugging. -- Wulfraed Dennis Lee Bieber AF6VN wlfraed(a)ix.netcom.com http://wlfraed.microdiversity.freeddns.org/

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why function throws an error?
by נתי שטרן June 28, 2022

June 28, 2022

def add_route(self, route): # """ Add a route object, but do not change the :data:`Route.app` # attribute.""" self.routes.append(route) self.router.add(route.rule, route.method, route, name=route.name ) # if DEBUG: route.prepare() -- <https://netanel.ml>

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