🌐 Mailman 3 March 2013 - Tutor - python.org

Scripting Calligra sheets with Python
by Jim Byrnes Jan. 31, 2022

Jan. 31, 2022

I am trying to script Calligra Sheets (formerly KSpread) with python. I have gotten some of the included example scripts to run so I know python scripting is running. I found the following snippet on their website: import KSpread sheet = KSpread.view().sheet() # swap text of B5 and C6 t1 = sheet.text("B5") t2 = sheet.text(6,3) sheet.setText("B5", t2) sheet.setText(6, 3, t1) # swap value of D7 and E8 v1 = sheet.value("D7") v2 = sheet.value(8,5) sheet.setValue("D7", v2) sheet.setValue(8, 5, v1) Error: 'str' object has no attribute 'text' File "file:///usr/share/kde4/apps/sheets/scripts/extensions/myswap.py", line 4, in <module> This error message appeared in a dialog box. I've taught myself some Python but I don't understand what is happening here. Shouldn't t1 be a sheet object? What would cause it to be a str instead? Thanks, Jim

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Wave module
by Alex Krycek Feb. 12, 2015

Feb. 12, 2015

Hello, I'm trying to join two .wav files with the wave module. But when I try to use wave.open(filename, "rb") I receive the following error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "F:\PortablePython1.0\lib\wave.py", line 483, in open return Wave_read(f) File "F:\PortablePython1.0\lib\wave.py", line 162, in __init__ self.initfp(f) File "F:\PortablePython1.0\lib\wave.py", line 143, in initfp self._read_fmt_chunk(chunk) File "F:\PortablePython1.0\lib\wave.py", line 264, in _read_fmt_chunk raise Error, 'unknown format: %r' % (wFormatTag,) wave.Error: unknown format: 85 I read somewhere that there are various wave formats, only some supported by Python. Is this true? If so, is there any way I can convert my wave files into a supported kind? Thanks!

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getUncPath(mappedDrive)
by Albert-Jan Roskam Jan. 31, 2014

Jan. 31, 2014

Hi, Is there a function that takes a file path with a mapped drive (z:\blah) and returns the associated UNC path (\\server\share\ding\dang\dong\blah)? I looked in os.path, but it doesn't seem to have this. The link below seems to be a solution (code in the bottom of the page), but I can't install win32com.client in the office :-( Is there any built-in function? http://stackoverflow.com/questions/2244767/python-check-network-map Thanks! Regards, Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

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How to unpack python-dateutil-2.0.tar.gz
by Richard D. Moores Sept. 5, 2013

Sept. 5, 2013

Python 3.2.3 64 bit MS Windows 7 Home Premium 64-bit SP1 I see python-dateutil recommended here from time to time, so I thought I'd try it out. I downloaded python-dateutil-2.1.tar.gz from http://pypi.python.org/pypi/python-dateutil but have forgotten how to unpack a .tar.gz file. Please remind me. Thanks, Dick Moores

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using ranges with argparse()
by Kurt Lieber July 20, 2013

July 20, 2013

Hi -- brand new to python, but trying to write a simple script that takes command line arguments. One of the arguments needs to test if a value is a) an integer and b) within a stated range. I currently have: parser.add_argument("-f", "--floor", default=6000, help="floor is the minimum amount of bonus points.",type=int, choices=range(5995, 6001)) This works, but when the user enters an out of bounds value, the help message is unfriendly: % ./bonus.py -f 10000 usage: bonus.py [-h] [-f {5995,5996,5997,5998,5999,6000}] MAM-bonus.py: error: argument -f/--floor: invalid choice: 10000 (choose from 5995, 5996, 5997, 5998, 5999, 6000) The problem is my default range is actually 0,10000 -- I changed it above for brevity's sake. So in the real world, it floods the screen to the point where it's unreadable. I can suppress the whole thing with argparse.SUPPRESS, but then I'm left with no help message at all. Is there a way to suppress the "(choose from 1,2,3,etc.)" part of the help message? Or a cleaner/different way altogether to accomplish the same thing? thanks.

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Phyton script for fasta file (seek help)
by michelle_low April 10, 2013

April 10, 2013

Hi everyone, Can someone please help me with the following phyton script? I received the error message DeprecationWarning: the sets module is deprecated from sets import Set. After googling, I have tried the methods others suggest: change sets to set or delete the from sets import Set but none of them works. Can someone suggest me how to modify the following codes so that the input file is read from standard input? I'd like to execute them with unix command script.py < sequence.fna Thanks a bunch. #!/usr/local/bin/python import math from sets import Set line = file("sequence.fna", "r") for x in line: if x [0] == ">" : #determine the length of sequences s=line.next() s=s.rstrip() length = len(s) # determine the GC content G = s.count('G') C = s.count('C') GC= 100 * (float(G + C) / length) stList = list(s) alphabet = list(Set(stList)) freqList = [] for symbol in alphabet: ctr = 0 for sym in stList: if sym == symbol: ctr += 1 freqList.append(float(ctr)/len(stList)) # Shannon entropy ent = 0.0 for freq in freqList: ent = ent + freq * math.log(freq, 2) ent = -ent print x print "Length:" , length print "G+C:" ,round(GC),"%" print 'Shannon entropy:' print ent print 'Minimum number of bits required to encode each symbol:' print int(math.ceil(ent))

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Set Reply-To field to Tutor@python.org
by Oscar Benjamin April 10, 2013

April 10, 2013

I have both sent and received messages on this list that went off-list by mistake. It's an easy mistake to make that you use reply instead of reply-all and then the message goes just to one person instead of the whole list. This problem is not unique to the python-tutor. I see it happening often on other mailing lists (often it's noticeable by the fact that someone forwards an off-list message back to the list which can sometimes break the threading of email software). One particular list that I receive has recently made an administrative change so that, from now on, all emails have the "Reply-To" header set to the list address. This means that the default behaviour when replying to a message is that the reply goes to the list. I think that this is the right thing to do by default since replying off-list is much less common and more likely to be something that you are consciously aware of when you do it. The change seems to have gone down well on the other list so I wondered: could it be done for this list as well? Oscar

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Help required
by Arijit Ukil April 4, 2013

April 4, 2013

I am new to python. My intention is to read the file digi.txt and store in separate arrays all the values of each columns. However, the following program prints only the last value, i.e. 1350696500.0. Please help to rectify this. f = open ("digi.txt", "r+") datafile = f.readlines() list_of_lists = datafile for data in list_of_lists: lstval = data.split (',') timest = float(lstval[0]) energy = float(lstval[1]) f.close() print timest Regards, Arijit Ukil Tata Consultancy Services Mailto: arijit.ukil(a)tcs.com Website: http://www.tcs.com ____________________________________________ Experience certainty. IT Services Business Solutions Outsourcing ____________________________________________ =====-----=====-----===== Notice: The information contained in this e-mail message and/or attachments to it may contain confidential or privileged information. If you are not the intended recipient, any dissemination, use, review, distribution, printing or copying of the information contained in this e-mail message and/or attachments to it are strictly prohibited. If you have received this communication in error, please notify us by reply e-mail or telephone and immediately and permanently delete the message and any attachments. Thank you

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The game of nim in python
by Yasin El Guennouni April 4, 2013

April 4, 2013

Hello, I am trying to modify a game of nim code. The game in the code works as: "You need to remove from 1 to 3 straws from the pile. The player that removes the final straw is the loser." But I would like it to be like the classic game, where you have 4 piles containing 1,3,5 and 7 sticks where the drawer of the last stick is the winner. It would be awsome if I could print how many sticks there are left in each pile, e.g. : I III IIIII IIIIIII. Thanks in advance! The code I have: player1=str(input("Enter your name. ")) player2="Computer" howMany=0 gameover=False strawsNumber=random.randint(10,20) if (strawsNumber%4)==1: strawsNumber+=1 def removingStrawsComputer(): removedNumber=random.randint(1,3) global strawsNumber while removedNumber>strawsNumber: removedNumber=random.randint(1,3) strawsNumber-=removedNumber return strawsNumber def removingStrawsHuman(): global strawsNumber strawsNumber-=howMany return strawsNumber def humanLegalMove(): global howMany legalMove=False while not legalMove: print("It's your turn, ",player1) howMany=int(input("How many straws do you want to remove?(from 1 to 3) ")) if howMany>3 or howMany<1: print("Enter a number between 1 and 3.") else: legalMove=True while howMany>strawsNumber: print("The entered number is greater than a number of straws remained.") howMany=int(input("How many straws do you want to remove?")) return howMany def checkWinner(player): if strawsNumber==0: print(player," wins.") global gameover gameover=True return gameover def resetGameover(): global gameover gameover=False return gameover def game(): while gameover==False: print("It's ",player2,"turn. The number of straws left: ",removingStrawsComputer()) checkWinner(player1) if gameover==True: break humanLegalMove() print("The number of straws left: ",removingStrawsHuman()) checkWinner(player2) game()

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Re: [Tutor] Tutor Digest, Vol 109, Issue 71
by Matthew Johnson April 4, 2013

April 4, 2013

I recently asked a question on SO: http://stackoverflow.com/questions/15180767/subset-list-based-on-value-of-d… and got very confused when trying to generalise the answer. The problem is as follows: say i have this list, and would like to get the value at each date that has the largest value for realtime_start (date) value. obs = [{'date': '2012-10-01', 'realtime_end': '2013-02-18', 'realtime_start': '2012-11-15', 'value': '231.751'}, {'date': '2012-10-01', 'realtime_end': '9999-12-31', 'realtime_start': '2012-12-19', 'value': '231.623'}, {'date': '2012-11-01', 'realtime_end': '2013-02-18', 'realtime_start': '2012-12-14', 'value': '231.025'}, {'date': '2012-11-01', 'realtime_end': '9999-12-31', 'realtime_start': '2013-01-19', 'value': '231.071'}, {'date': '2012-12-01', 'realtime_end': '2013-02-18', 'realtime_start': '2013-01-16', 'value': '230.979'}, {'date': '2012-12-01', 'realtime_end': '9999-12-31', 'realtime_start': '2013-02-19', 'value': '231.137'}, {'date': '2012-12-01', 'realtime_end': '9999-12-31', 'realtime_start': '2013-03-19', 'value': '231.197'}, {'date': '2013-01-01', 'realtime_end': '9999-12-31', 'realtime_start': '2013-02-21', 'value': '231.198'}, {'date': '2013-01-01', 'realtime_end': '9999-12-31', 'realtime_start': '2013-03-21', 'value': '231.222'}] maxDate = "2013-02-21" The answer suggested itertools, and it worked for the exact maxDate that's above. However, when i move the date (say to "2013-01-21") it throws the error: ValueError: max() arg is an empty sequence. I can see from the list that there are elements that have realtime_start values that are lower than 2013-01-21 so this is a bug. I have read the documents for itertools, but cannot quite work out this groupby stuff. there's a snip of the SO solution below -- help understanding as well as the bug fix would be much appreciated. thanks in advance, Matt Johnson ______ ## subset on maxDate grouped2 = itertools.groupby(obs, lambda x: x['date']) m2 = [max((w for w in g if w['realtime_start'] <= maxDate), key=lambda x: x['realtime_start']) for k, g in grouped2] pprint.pprint(m2) On 21/03/2013, at 8:30 AM, "tutor-request(a)python.org" < tutor-request(a)python.org> wrote: Send Tutor mailing list submissions to tutor(a)python.org To subscribe or unsubscribe via the World Wide Web, visit http://mail.python.org/mailman/listinfo/tutor or, via email, send a message with subject or body 'help' to tutor-request(a)python.org You can reach the person managing the list at tutor-owner(a)python.org When replying, please edit your Subject line so it is more specific than "Re: Contents of Tutor digest..." Today's Topics: 1. Re: Help (Dave Angel) 2. Re: Help (xDog Walker) 3. Re: Help (Robert Sjoblom) 4. Re: Scripting Calligra sheets with Python (Jim Byrnes) 5. Re: Help (Alan Gauld) ---------------------------------------------------------------------- Message: 1 Date: Wed, 20 Mar 2013 16:53:19 -0400 From: Dave Angel <davea(a)davea.name> To: tutor(a)python.org Subject: Re: [Tutor] Help Message-ID: <514A21BF.9030303(a)davea.name> Content-Type: text/plain; charset=ISO-8859-1; format=flowed On 03/20/2013 03:57 PM, travis jeanfrancois wrote: Hello, I am a beginning python student and I am having trouble with a program I am writing . The problem requires me to use "while" and that I create a function that allows the user to a create sentence by inputing a string and to end the sentence with a period meaning inputing "." .The problem is while keeps overwriting the previuos input and it still asks for a string even after it prints out . Here is the output I am getting Enter the first word in your sentence: I Enter the next word in your sentence: am Enter the next word in your sentence: a Enter the next word in your sentence: novice Enter the next word in your sentence: . I . . Enter the next word in your sentence: Here is the desired output: : Enter the first word in your sentence: I Enter the next word in your sentence: am Enter the next word in your sentence: a Enter the next word in your sentence: novice Enter the next word in your sentence: . I am a novice. Here is my code: def B1(): #Creates a function called B1 period = "." # The variable period is assigned first = input("Enter the first word in your sentence ") #The variable first is assigned next1 = input("Enter the next word in you sentence or enter period:") #The variable next 1 is assigned # I need store the value so when while overwrites next1 with the next input the previous input is stored and will print output when I call it later along with last one # I believe the solution is some how implenting this expression x = x+ variable You need a new variable that accumulates the whole sentence. I'd use a list, but many people would use a string. Since I don't know what concepts you know yet, I'll stick to string here. Anyway, you have to initialize it before the loop, and then you can print it after the loop. sentence = "" while next1 != (period) : next1 = input("Enter the next word in you sentence or enter period:") At this point, add the word to the sentence. if next1 == (period): next1 = next1 + period print ("Your sentence is:",first,next1,period) No need for these three lines inside the loop, since the loop will end when next1 is equal to the period. So put the print after the end of the loop, and I'll let you figure out what it should print. PS : The" #" is I just type so I can understand what each line does -- DaveA ------------------------------ Message: 2 Date: Wed, 20 Mar 2013 14:47:39 -0700 From: xDog Walker <thudfoo(a)gmail.com> To: tutor(a)python.org Subject: Re: [Tutor] Help Message-ID: <201303201447.39643.thudfoo(a)gmail.com> Content-Type: text/plain; charset="iso-8859-1" On Wednesday 2013 March 20 13:39, Robert Sjoblom wrote: A word of advice: next is a keyword in python ~/Packages/Python/Notable-0.1.5b> python Python 2.5 (r25:51908, May 25 2007, 16:14:04) [GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux2 Type "help", "copyright", "credits" or "license" for more information. import keyword keyword.iskeyword('next') False 14:44 Wed 2013 Mar 20 ~/Packages/Python/Notable-0.1.5b> python2.7 Python 2.7.2 (default, Oct 10 2011, 10:47:36) [GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux2 Type "help", "copyright", "credits" or "license" for more information. import keyword keyword.iskeyword('next') False 14:44 Wed 2013 Mar 20 ~/Packages/Python/Notable-0.1.5b> python3.3 Python 3.3.0 (default, Sep 30 2012, 09:02:56) [GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux Type "help", "copyright", "credits" or "license" for more information. import keyword keyword.iskeyword('next') False -- Yonder nor sorghum stenches shut ladle gulls stopper torque wet strainers. ------------------------------ Message: 3 Date: Wed, 20 Mar 2013 22:59:04 +0100 From: Robert Sjoblom <robert.sjoblom(a)gmail.com> To: xDog Walker <thudfoo(a)gmail.com> Cc: Tutor - python List <tutor(a)python.org> Subject: Re: [Tutor] Help Message-ID: <CAJKU7g2bdCHgza-48xw+5C_7kq592G=p3qxHbE61dUqZQcoTuA(a)mail.gmail.com> Content-Type: text/plain; charset="iso-8859-1" On Mar 20, 2013 10:49 p.m., "xDog Walker" <thudfoo(a)gmail.com> wrote: On Wednesday 2013 March 20 13:39, Robert Sjoblom wrote: A word of advice: next is a keyword in python ~/Packages/Python/Notable-0.1.5b> python Python 2.5 (r25:51908, May 25 2007, 16:14:04) [GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux2 Type "help", "copyright", "credits" or "license" for more information. import keyword keyword.iskeyword('next') False 14:44 Wed 2013 Mar 20 ~/Packages/Python/Notable-0.1.5b> python2.7 Python 2.7.2 (default, Oct 10 2011, 10:47:36) [GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux2 Type "help", "copyright", "credits" or "license" for more information. import keyword keyword.iskeyword('next') False 14:44 Wed 2013 Mar 20 ~/Packages/Python/Notable-0.1.5b> python3.3 Python 3.3.0 (default, Sep 30 2012, 09:02:56) [GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux Type "help", "copyright", "credits" or "license" for more information. import keyword keyword.iskeyword('next') False -- Yonder nor sorghum stenches shut ladle gulls stopper torque wet strainers. Fine, it's a method, my bad.

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