🌐 Mailman 3 May 2013 - Tutor - python.org

Scripting Calligra sheets with Python
by Jim Byrnes Jan. 31, 2022

Jan. 31, 2022

I am trying to script Calligra Sheets (formerly KSpread) with python. I have gotten some of the included example scripts to run so I know python scripting is running. I found the following snippet on their website: import KSpread sheet = KSpread.view().sheet() # swap text of B5 and C6 t1 = sheet.text("B5") t2 = sheet.text(6,3) sheet.setText("B5", t2) sheet.setText(6, 3, t1) # swap value of D7 and E8 v1 = sheet.value("D7") v2 = sheet.value(8,5) sheet.setValue("D7", v2) sheet.setValue(8, 5, v1) Error: 'str' object has no attribute 'text' File "file:///usr/share/kde4/apps/sheets/scripts/extensions/myswap.py", line 4, in <module> This error message appeared in a dialog box. I've taught myself some Python but I don't understand what is happening here. Shouldn't t1 be a sheet object? What would cause it to be a str instead? Thanks, Jim

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Wave module
by Alex Krycek Feb. 12, 2015

Feb. 12, 2015

Hello, I'm trying to join two .wav files with the wave module. But when I try to use wave.open(filename, "rb") I receive the following error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "F:\PortablePython1.0\lib\wave.py", line 483, in open return Wave_read(f) File "F:\PortablePython1.0\lib\wave.py", line 162, in __init__ self.initfp(f) File "F:\PortablePython1.0\lib\wave.py", line 143, in initfp self._read_fmt_chunk(chunk) File "F:\PortablePython1.0\lib\wave.py", line 264, in _read_fmt_chunk raise Error, 'unknown format: %r' % (wFormatTag,) wave.Error: unknown format: 85 I read somewhere that there are various wave formats, only some supported by Python. Is this true? If so, is there any way I can convert my wave files into a supported kind? Thanks!

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getUncPath(mappedDrive)
by Albert-Jan Roskam Jan. 31, 2014

Jan. 31, 2014

Hi, Is there a function that takes a file path with a mapped drive (z:\blah) and returns the associated UNC path (\\server\share\ding\dang\dong\blah)? I looked in os.path, but it doesn't seem to have this. The link below seems to be a solution (code in the bottom of the page), but I can't install win32com.client in the office :-( Is there any built-in function? http://stackoverflow.com/questions/2244767/python-check-network-map Thanks! Regards, Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

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keyboard interrupt
by Jim Mooney Oct. 17, 2013

Oct. 17, 2013

I made a simple ear frequency-tester, but I don't want it to go on forever, so I tried stopping it when I pressed a key, as below, but that doesn't work. I did check out keyboard interrupts but they seem unnecessarily complex just to stop a program. I'm not passing keys. Is there something simple I'm missing? import winsound try: for freq in range(100,32000,100): winsound.Beep(freq, 1000) except KeyboardInterrupt: pass -- Jim Mooney

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How to unpack python-dateutil-2.0.tar.gz
by Richard D. Moores Sept. 5, 2013

Sept. 5, 2013

Python 3.2.3 64 bit MS Windows 7 Home Premium 64-bit SP1 I see python-dateutil recommended here from time to time, so I thought I'd try it out. I downloaded python-dateutil-2.1.tar.gz from http://pypi.python.org/pypi/python-dateutil but have forgotten how to unpack a .tar.gz file. Please remind me. Thanks, Dick Moores

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using ranges with argparse()
by Kurt Lieber July 20, 2013

July 20, 2013

Hi -- brand new to python, but trying to write a simple script that takes command line arguments. One of the arguments needs to test if a value is a) an integer and b) within a stated range. I currently have: parser.add_argument("-f", "--floor", default=6000, help="floor is the minimum amount of bonus points.",type=int, choices=range(5995, 6001)) This works, but when the user enters an out of bounds value, the help message is unfriendly: % ./bonus.py -f 10000 usage: bonus.py [-h] [-f {5995,5996,5997,5998,5999,6000}] MAM-bonus.py: error: argument -f/--floor: invalid choice: 10000 (choose from 5995, 5996, 5997, 5998, 5999, 6000) The problem is my default range is actually 0,10000 -- I changed it above for brevity's sake. So in the real world, it floods the screen to the point where it's unreadable. I can suppress the whole thing with argparse.SUPPRESS, but then I'm left with no help message at all. Is there a way to suppress the "(choose from 1,2,3,etc.)" part of the help message? Or a cleaner/different way altogether to accomplish the same thing? thanks.

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2 basic problems
by charles benoit June 16, 2013

June 16, 2013

1:Python 2.7.4 (default, Apr 19 2013, 18:32:33) [GCC 4.7.3] on linux2 Type "copyright", "credits" or "license()" for more information. >>> 4+4 8 >>> 3+3=4 SyntaxError: can't assign to operator >>> 3=1 SyntaxError: can't assign to literal > I thought the last 2 lines should return False 2: lot=('1'+'6'+'8') print(lot) a=open("acc","w") a.write(lot) a.close b=open("acc","r") b.read() print (b) b.close returns >>> 168 <open file 'acc', mode 'r' at 0xb6f9a650> >>> I thought I was saving a string to a file and reading and printing the string. The output looks like a description of the IO textwrapper at some location. I'm sure this is a syntax/format problem.but this like the other examples I saw. I ran this using python 2.6.7 on ubuntu 13.0 Thank you for any help

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Argparse functions with N parameters
by Danilo Chilene June 7, 2013

June 7, 2013

Hello, I have the code below: import argparse class Myclass(object): def foo(self): print 'foo' def bar(self): print 'bar' def test(self,name,place): print name, place class Main(Myclass): def __init__(self): foo_parser = argparse.ArgumentParser() foo_parser.add_argument('method') self.args = foo_parser.parse_args() def __call__(self, *args, **kws): method = self.args.method return getattr(self, method)(*args, **kws) if __name__ == "__main__": main = Main() main() It's working for functions foo and bar: 5: python arg.py foo foo 5: python arg.py bar bar 5: python arg.py test a b usage: arg.py [-h] method arg.py: error: unrecognized arguments: a b But for function test I guess I'm missing something, the idea is to have N functions and N param. Any ideas? Best Regards, Danilo

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Project Euler #8
by Nick Shemonsky June 1, 2013

June 1, 2013

Hey there everybody. I'm new to python and am attempting to teach myself to code while brushing up on my math skills via the problems at projecteuler.net. My solutions thus far have been mostly brute force and this is no exception but I'm having an issue with tackling some iteration in the problem. Essentially, the problem is to find the largest product of 5 consecutive digits in a random series of numbers. I'm trying to get things working on a very small string to start... my code thus far is below. I begin by getting a list of strings from the original string, only keeping those that are 5 digits long... then those numbers are converted to integers and I get the product with the product function. As you can see, I'm currently doing it only for the string of 12345 stored at strings[0]. If I run that list comprehension as [int(i) for i in strings], I get a new list of all the integers I want; 12345, 23456, 34567, etc... but I can no longer iterate through to multiply them all together... I feel like I need to either pull each individual string apart first and temporarily store it then convert each to an int and get the product or instead, just find a way to iterate through the members of a member of a list... I've read up on a bunch of stuff regarding map(), zip() and enumerate() but none of it seems to be applicable here or maybe I'm misunderstanding it. Once I have a list of products a simple max() should do the trick... or maybe it'd be quicker to compare a to b through each iteration and just keep the larger product rather than creating a giant list of products once I get this step working? Any ideas towards the next step would be much appreciated. str_num = '1234567890' n = 5 strings = [str_num[i:i+5] for i in range(0, len(str_num)) if len(str_num[i:i+5])==5] integers = [int(i) for i in strings[0]] def product(x): p = 1 for n in integers: p*=n return p print product(integers) Thanks in advance! Nick

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got text switched
by Jim Mooney May 31, 2013

May 31, 2013

Oops, Gmail switched me back to rich text. My apologies. Back to plain ;') I wish I could automate the mode, per-recipient, since I do need rich text for some things. The way gmail defaults seems to change from month to month. -- Jim Mooney

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