🌐 Mailman 3 July 2018 - Tutor - python.org

Scripting Calligra sheets with Python
by Jim Byrnes Jan. 31, 2022

Jan. 31, 2022

I am trying to script Calligra Sheets (formerly KSpread) with python. I have gotten some of the included example scripts to run so I know python scripting is running. I found the following snippet on their website: import KSpread sheet = KSpread.view().sheet() # swap text of B5 and C6 t1 = sheet.text("B5") t2 = sheet.text(6,3) sheet.setText("B5", t2) sheet.setText(6, 3, t1) # swap value of D7 and E8 v1 = sheet.value("D7") v2 = sheet.value(8,5) sheet.setValue("D7", v2) sheet.setValue(8, 5, v1) Error: 'str' object has no attribute 'text' File "file:///usr/share/kde4/apps/sheets/scripts/extensions/myswap.py", line 4, in <module> This error message appeared in a dialog box. I've taught myself some Python but I don't understand what is happening here. Shouldn't t1 be a sheet object? What would cause it to be a str instead? Thanks, Jim

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guess my number game (reversed)
by chiara pascucci Oct. 6, 2018

Oct. 6, 2018

Hello. I am very new to learning Python, and I would need some help with a little game I am trying to write. I am trying to write a game where the user is asked to think of a number from 1 to a 100, and the computer tries to guess it. Now, after every guess I would want the programme to ask whether its guess is right, too low, or too high, and then take another guess based on the user's input. The programme works fine if the it guesses the number right on its first try, but when the users inputs "too low" or "too high" an infinite loop is returned. I thinkI have done something wrong in my while loop and that my sentry variable is somehow wrong -but I can't seem to be able to fix it! Any help or commments would be very appreciated. Below is the code written so far Many thanks Chiara print("think of a number from 1 to 100") print("I will try and guess it!") import random number = random.randint(1,100) print(number) answer = input("is this right, too high, or too low?") while answer != "right": if answer == "too high": number2 = random.randint(1,number) print(number2) elif answer == "too low": number3 = random.randint(number,100) print(number3) print("I finally guessed your number. Thank you for playing") input("\n\nPress enter key to exit")

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SSL Error
by Saket Mehrotra Aug. 2, 2018

Aug. 2, 2018

Hi I am trying to run import requests in a py file but I am getting below error ssl.PROTOCOL_SSLv23: OpenSSL.SSL.SSLv23_METHOD, AttributeError: module 'ssl' has no attribute 'PROTOCOL_SSLv23' >>> I tried to execute below from the terminal but it still remains unresolved. sudo easy_install --upgrade pip I've also had to run: sudo pip uninstall pyopenssl sudo pip install mozdownload Can you please help me . Thanks & Regards Saket Mehrotra

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Python Memory Allocation -- deep learning
by Sunil Tech July 30, 2018

July 30, 2018

Hi Team, I am investigating how the memory allocation happens in Python For Eg: *Case 1:* >>> a = 10 >>> b = 10 >>> c = 10 >>> id(a), id(b), id(c) (140621897573616, 140621897573616, 140621897573616) >>> a += 1 >>> id(a) 140621897573592 *Case 2:* >>> x = 500 >>> y = 500 >>> id(x) 4338740848 >>> id(y) 4338741040 *Case 3:* >>> s1 = 'hello' >>> s2 = 'hello' >>> id(s1), id(s2) (4454725888, 4454725888) >>> s1 == s2 True >>> s1 is s2 True >>> s3 = 'hello, world!' >>> s4 = 'hello, world!' >>> id(s3), id(s4) (4454721608, 4454721664) >>> s3 == s4 True >>> s3 is s4 False Python memory allocation is varying in all these use cases. Please help me understand. Thanks, Sunil. G

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How to add an Image in Grid mode with Python and Tkinter?
by Matthew Polack July 30, 2018

July 30, 2018

Hi, Steadily trying to learn Python and Tkinter here with our students... Am working on a simple 'Price of Cereal Crop' calculator....and have made a start with the code below... I'm trying to simply add an image to our program to make the GUI more interesting...but most of the tutorials describe using the 'Pack' method.... not the grid method of layout... and apparently you cannot use 'Pack' and 'Grid' in the one program... Can anyone explain how I could add an image to this program? Or show me an example of a simple program that lets someone simply add an image and use the grid layout in combination. Thanks for any clues at all! - Matt from tkinter import * root = Tk("Crop Calculator") # abutton = Button(root, text="Crop Prices in Australia") #Main Heading Labels croplabel = Label(root, text="Crop Prices in Australia", fg="white", bg= "green") instruction = Label(root, text="Please select from the following crops", fg= "green", bg="white") blanklabel = Label(root, text="", fg="green", bg="white") blanklabel2 = Label(root, text="", fg="green", bg="white") statusbar = Label(root, text="Copyright 2018", fg="white", bg="black", relief='sunken') #Answerlabel answerlabel=Label(root, text="wheatwords") # abutton.pack(side='left', fill='both', expand=True) croplabel.grid(columnspan=12, sticky='ew') instruction.grid(row=1, columnspan=12, sticky='ew') blanklabel.grid(row=2, columnspan=12, sticky='ew') statusbar.grid(row=12, columnspan=12, sticky='ew') blanklabel2.grid(row=11, columnspan=12, sticky='ew') #List of Crops wheatlabel = Button(root, text="Wheat", fg="black", bg="yellow") peaslabel = Button(root, text="Peas", fg="white", bg="green") lupenslabel = Button(root, text="Lupens", fg="white", bg="brown") barleylabel = Button(root, text="Barley", fg="white", bg="orange") canolalabel = Button(root, text="Canola", fg="white", bg="red") sorghumlabel = Button(root, text="Sorghum", fg="white", bg="ivory3") # Grid positioning of crops. wheatlabel.grid(row=4, column=1, sticky='ew') peaslabel.grid(row=4, column=7, sticky='ew') lupenslabel.grid(row=5, column=1, sticky='ew') barleylabel.grid(row=5, column=7, sticky='ew') canolalabel.grid(row=6, column=1, sticky='ew') sorghumlabel.grid(row=6, column=7, sticky='ew') # Definitions def wheatwords(): print("Button one was pushed") wheatlabel.configure(command=wheatwords) root.mainloop() -- **Disclaimer: *Whilst every attempt has been made to ensure that material contained in this email is free from computer viruses or other defects, the attached files are provided, and may only be used, on the basis that the user assumes all responsibility for use of the material transmitted. This email is intended only for the use of the individual or entity named above and may contain information that is confidential and privileged. If you are not the intended recipient, please note that any dissemination, distribution or copying of this email is strictly prohibited. If you have received this email in error, please notify us immediately by return email or telephone +61 3 5382 2529** and destroy the original message.*

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Dictionary viceversa
by Valerio Pachera July 30, 2018

July 30, 2018

Hi all, consider this dictionary users = {'user1':['office-a', 'office-b'], 'user2':['office-b'], 'user3':['office-a','office-c']} It's a list of users. For each user there's a list of room it can access to. Generalizing, a dictionary with a list for each element. d = {k:list} I wish to get the same info but "sorted" by room. In other words, a dictionary that has rooms as keys. For each room there's a list of users that can access the room. I've been able to achieve that by for user in users: for room in users[user]: if room in users_by_room: users_by_room[room].append(user) else: users_by_room[room] = [] users_by_room[room].append(user) And i generalized it in a function like this: def viceversa(d): new_d = dict() for k in d: for e in d[k]: if e in new_d: new_d[e].append(k) else: new_d[e] = [] new_d[e].append(k) return(new_d) My question is: is there a better way to that? Maybe by list comprehension? I was looking to substiture the cicle for e in new_d like this: [ new_d[e].append(k) if e in new_d else new_d[e].append(k) for e in d[k] ] but it can't work because 'new_d[e] = []' is missing.

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Do something on list elements
by Valerio Pachera July 30, 2018

July 30, 2018

Hi all, I started studying python and I hope you may help me getting better. Let's start with the first question. Consider this example --- #!/usr/bin/python3 l = ['unoX', 'dueX'] c = 0 for n in l: l[c] = l[c].replace('X','') c = c + 1 print (l) --- it works but I wonder if there's a better way to achieve the same.

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Questions about the formatting of docstrings
by boB Stepp July 28, 2018

July 28, 2018

I am near the end of reading "Documenting Python Code: A Complete Guide" by James Mertz, found at https://realpython.com/documenting-python-code/ This has led me to a few questions: (1) The author claims that reStructuredText is the official Python documentation standard. Is this true? If yes, is this something I should be doing for my own projects? (2) How would type hints work with this reStructuredText formatting? In part of the author's reStructuredText example he has: [...] :param file_loc: The file location of the spreadsheet :type file_loc: str [...] It seems to me that if type hinting is being used, then the ":type" info is redundant, so I wonder if special provision is made for avoiding this redundancy when using type hinting? TIA! -- boB

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how to change the command "string" on a tkinter Button?
by Chris Roy-Smith July 28, 2018

July 28, 2018

Hi, OS is Linux, Python version is 3.6.5 I am trying to change the command of a tkinter Button in my program. Eventually I want to be able to do this to many buttons. My attempt at code brings up no error messages, but the button appears to do nothing. I really have no idea how to do this, but this is what I wrote. ==================================== #!/usr/bin/python3 from tkinter import * class form(object): def __init__(self, x, reply, master, z,bu): self.x=x self.reply=reply self.master=master self.z=z self.bu=bu def change(x, reply, z, b): #f contains the alternative command (as a string) f=["lambda x=vars, txt=reply,fu=0 bu=b1 :form.change(x, txt, fu, bu)", "lambda x=vars, txt=first, fu=1 bu=b1: form.change(x, txt, fu, bu)"] for i in range(4): x[i].set(reply[i]) #attempt to change command clause set.button(f[z]) def draw(master): vars = [] label = [] button = StringVar for i in range(4): var = StringVar() vars.append(var) label.append("") label[i] = Label( master, textvariable=var, relief=RAISED ).grid(row=i, column=0) vars[i].set(first[i]) b1=Button(master, text="change", command=button).grid(row=i+1, column=0) reply=["now I don't know", "Happy birthday", "Many happy returns", "Next it's my turn",1] first=["What's your name?", "My name is Fred", "I have just had my birthday", "your's is next!",2] master=Tk() form.draw(master) master.mainloop() ================================= How should I do this, I had worked around the problem by destroying the window and building it again, but it was pointed out that I have an unusual coding style doing this. All hints appreciated! Regards, Chris Roy-Smith

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How can I find a group of characters in a list of strings?
by Jim July 26, 2018

July 26, 2018

Linux mint 18 and python 3.6 I have a list of strings that contains slightly more than a million items. Each item is a string of 8 capital letters like so: ['MIBMMCCO', 'YOWHHOY', ...] I need to check and see if the letters 'OFHCMLIP' are one of the items in the list but there is no way to tell in what order the letters will appear. So I can't just search for the string 'OFHCMLIP'. I just need to locate any strings that are made up of those letters no matter their order. I suppose I could loop over the list and loop over each item using a bunch of if statements exiting the inner loop as soon as I find a letter is not in the string, but there must be a better way. I'd appreciate hearing about a better way to attack this. thanks, Jim

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