🌐 Mailman 3 January 2020 - Tutor - python.org

Scripting Calligra sheets with Python
by Jim Byrnes Jan. 31, 2022

Jan. 31, 2022

I am trying to script Calligra Sheets (formerly KSpread) with python. I have gotten some of the included example scripts to run so I know python scripting is running. I found the following snippet on their website: import KSpread sheet = KSpread.view().sheet() # swap text of B5 and C6 t1 = sheet.text("B5") t2 = sheet.text(6,3) sheet.setText("B5", t2) sheet.setText(6, 3, t1) # swap value of D7 and E8 v1 = sheet.value("D7") v2 = sheet.value(8,5) sheet.setValue("D7", v2) sheet.setValue(8, 5, v1) Error: 'str' object has no attribute 'text' File "file:///usr/share/kde4/apps/sheets/scripts/extensions/myswap.py", line 4, in <module> This error message appeared in a dialog box. I've taught myself some Python but I don't understand what is happening here. Shouldn't t1 be a sheet object? What would cause it to be a str instead? Thanks, Jim

5 8

Corrupt file(s) likelihood and prevention?
by boB Stepp Feb. 2, 2020

Feb. 2, 2020

I just finished reading a thread on the main list that got a little testy. The part that is piquing my interest was some discussion of data files perhaps getting corrupted. I have wondered about this off and on. First what is the likelihood nowadays of a file becoming corrupted, and, second, what steps should one take to prevent/minimize this from happening? I notice that one of the applications I work with at my job apparently uses checksums to detect when one of its files gets modified from outside of the application. -- boB

6 11

Input is Dictionary1, Output is Dictionary2 (using keys and values of Dictionary1)
by Panchanathan Suresh Feb. 2, 2020

Feb. 2, 2020

Hi Everyone, I spent a lot of time on this, trying out many things, but I am unable to create a new dictionary with the users as keys and a list of their groups as values. Input Dictionary is {"local": ["admin", "userA"],"public": ["admin", "userB"],"administrator": ["admin"] } Expected Output Dictionary is {"userA": ["admin","public"], "userB": ["admin"], "administrator": ["admin"]} --- How to create an unique group for a particular user? --- And then how to add this user key and the user's value (which will be the list of groups the user belongs to) ***** def groups_per_user(group_dictionary): user_groups = {} groups = [] # Go through group_dictionary for group,user in group_dictionary.items(): # Now go through the users in the group for user1 in user: groups.append(group) print(user1,groups) return(user_groups) print(groups_per_user({"local": ["admin", "userA"],"public": ["admin", "userB"],"administrator": ["admin"] })) ***** Thanks so much

4 4

Printing Bold Text
by Adam Slowley Feb. 1, 2020

Feb. 1, 2020

So I’m a beginner, learning Python for the first time so this might be a dumb question but here goes. I’m trying to print a text in bold. For example: def main(): name=input("Enter your name:") print("You entered for name a value of",name) I want whatever the user inputs as his/her name to be printed in Bold

3 3

Regarding learning python
by faslur rahman Jan. 31, 2020

Jan. 31, 2020

I am faslur rahman from Sri Lanka, last six months i was trying to learn python programming by my self, But unfortunately i did not found any good resource to learn about python. Even i try from python website, there I got some books to refer and this email ID also. can you please advise me where to learn python full course?. Thank you

5 5

Re: [Tutor] Input is Dictionary1, Output is Dictionary2 (using keys and values of Dictionary1)
by Panchanathan Suresh Jan. 31, 2020

Jan. 31, 2020

Thanks a lot Mats and David! I am not yet that familiar with data structures. This statement indeed works: user_groups[user].append(group) But how can we use 'append' keyword for a dictionary? Is not append used only for appending to a List? Is it because Group is a already a List in the original dictionary? This is a bit confusing... Can we append to the list of dictionary values for a given key, using Append command? On Thu, Jan 30, 2020 at 2:52 PM <tutor-request(a)python.org> wrote: > Send Tutor mailing list submissions to > tutor(a)python.org > > To subscribe or unsubscribe via the World Wide Web, visit > https://mail.python.org/mailman/listinfo/tutor > or, via email, send a message with subject or body 'help' to > tutor-request(a)python.org > > You can reach the person managing the list at > tutor-owner(a)python.org > > When replying, please edit your Subject line so it is more specific > than "Re: Contents of Tutor digest..." > Today's Topics: > > 1. Regarding learning python (faslur rahman) > 2. Input is Dictionary1, Output is Dictionary2 (using keys and > values of Dictionary1) (Panchanathan Suresh) > 3. Re: Regarding learning python (Alan Gauld) > 4. Re: Input is Dictionary1, Output is Dictionary2 (using keys > and values of Dictionary1) (Mats Wichmann) > 5. Re: Input is Dictionary1, Output is Dictionary2 (using keys > and values of Dictionary1) (David L Neil) > > > > ---------- Forwarded message ---------- > From: faslur rahman <frahmanf89(a)gmail.com> > To: tutor(a)python.org > Cc: > Bcc: > Date: Thu, 30 Jan 2020 20:22:19 +0300 > Subject: [Tutor] Regarding learning python > I am faslur rahman from Sri Lanka, last six months i was trying to learn > python programming by my self, But unfortunately i did not found any good > resource to learn about python. Even i try from python website, there I got > some books to refer and this email ID also. > can you please advise me where to learn python full course?. > > Thank you > > > > > ---------- Forwarded message ---------- > From: Panchanathan Suresh <suresh.gm(a)gmail.com> > To: tutor(a)python.org > Cc: > Bcc: > Date: Thu, 30 Jan 2020 12:23:47 -0800 > Subject: [Tutor] Input is Dictionary1, Output is Dictionary2 (using keys > and values of Dictionary1) > Hi Everyone, > > I spent a lot of time on this, trying out many things, but I am unable to > create a new dictionary with the users as keys and a list of their groups > as values. > > Input Dictionary is {"local": ["admin", "userA"],"public": ["admin", > "userB"],"administrator": ["admin"] } > Expected Output Dictionary is {"userA": ["admin","public"], "userB": > ["admin"], "administrator": ["admin"]} > > --- How to create an unique group for a particular user? > --- And then how to add this user key and the user's value (which will be > the list of groups the user belongs to) > > ***** > def groups_per_user(group_dictionary): > user_groups = {} > groups = [] > # Go through group_dictionary > for group,user in group_dictionary.items(): > # Now go through the users in the group > for user1 in user: > groups.append(group) > print(user1,groups) > > return(user_groups) > > print(groups_per_user({"local": ["admin", "userA"],"public": ["admin", > "userB"],"administrator": ["admin"] })) > > ***** > > Thanks so much > > > > > ---------- Forwarded message ---------- > From: Alan Gauld <alan.gauld(a)yahoo.co.uk> > To: tutor(a)python.org > Cc: > Bcc: > Date: Thu, 30 Jan 2020 21:32:58 +0000 > Subject: Re: [Tutor] Regarding learning python > On 30/01/2020 17:22, faslur rahman wrote: > > I am faslur rahman from Sri Lanka, last six months i was trying to learn > > python programming by my self, But unfortunately i did not found any good > > resource to learn about python. > > It would help if you can be more specific about what was > wrong with the resources you tried. > > Also what is your background? Can you program in other languages, > is it just python you ate struggling with? Or are you new to > programming itself, in which case there are a lot of concepts > to learn as well as how they are done in python. > > > Even i try from python website, there I got > > some books to refer and this email ID also. > > The official tutorial is very good if you can already program > in another language. But it is not so good for total beginners. > Thats where the non programmers page comes into play... > > > can you please advise me where to learn python full course?. > > Well, obviously I can't resist the opportunity to push my > tutorial - see my signature below... :-) > > And if you get stuck (in any tutorial, not just mine) ask > specific questions here. Send the code that doesn't work, > any errors you get, tell us what you expected to happen > and what did happen./ Then we can help/explain. > > Also tell us whether you are using Python 2 or 3. > I strongly recommend using Python 3 and making sure > your chosen tutorial also uses it. > > -- > Alan G > Author of the Learn to Program web site > http://www.alan-g.me.uk/ > http://www.amazon.com/author/alan_gauld > Follow my photo-blog on Flickr at: > http://www.flickr.com/photos/alangauldphotos > > > > > > > ---------- Forwarded message ---------- > From: Mats Wichmann <mats(a)wichmann.us> > To: tutor(a)python.org > Cc: > Bcc: > Date: Thu, 30 Jan 2020 14:47:15 -0700 > Subject: Re: [Tutor] Input is Dictionary1, Output is Dictionary2 (using > keys and values of Dictionary1) > On 1/30/20 1:23 PM, Panchanathan Suresh wrote: > > Hi Everyone, > > > > I spent a lot of time on this, trying out many things, but I am unable to > > create a new dictionary with the users as keys and a list of their groups > > as values. > > > > Input Dictionary is {"local": ["admin", "userA"],"public": ["admin", > > "userB"],"administrator": ["admin"] } > > Expected Output Dictionary is {"userA": ["admin","public"], "userB": > > ["admin"], "administrator": ["admin"]} > > > > --- How to create an unique group for a particular user? > > --- And then how to add this user key and the user's value (which will be > > the list of groups the user belongs to) > > > > ***** > > def groups_per_user(group_dictionary): > > user_groups = {} > > groups = [] > > # Go through group_dictionary > > for group,user in group_dictionary.items(): > > # Now go through the users in the group > > for user1 in user: > > groups.append(group) > > print(user1,groups) > > > > return(user_groups) > > > > print(groups_per_user({"local": ["admin", "userA"],"public": ["admin", > > "userB"],"administrator": ["admin"] })) > > > > ***** > > Hopefully this isn't a homework problem :) > > You're not adding anything to your new dictionary. What you want to do > is use the user as a key, and a list of groups as the value; the trick > is that you may need to add several times to a user's entry, so you need > to handle both the case of "user not yet in dictionary" and the case of > "user has a grouplist, add to that list". As a quick and dirty hack, > like this (I changed a name a bit for clarity): > > for group, userlist in group_dictionary.items(): > # Now go through the users in the group > for user in userlist: > try: > user_groups[user].append(group) > except KeyError: > user_groups[user] = [group] > > > > > > ---------- Forwarded message ---------- > From: David L Neil <PyTutor(a)danceswithmice.info> > To: tutor(a)python.org > Cc: > Bcc: > Date: Fri, 31 Jan 2020 11:51:38 +1300 > Subject: Re: [Tutor] Input is Dictionary1, Output is Dictionary2 (using > keys and values of Dictionary1) > Greetings Suresh! > What is your level of Python skill? > ... skills with data structures? > > > On 31/01/20 9:23 AM, Panchanathan Suresh wrote: > > Hi Everyone, > > > > I spent a lot of time on this, trying out many things, but I am unable to > > create a new dictionary with the users as keys and a list of their groups > > as values. > > > > Input Dictionary is {"local": ["admin", "userA"],"public": ["admin", > > "userB"],"administrator": ["admin"] } > > Expected Output Dictionary is {"userA": ["admin","public"], "userB": > > ["admin"], "administrator": ["admin"]} > > > > --- How to create an unique group for a particular user? > > --- And then how to add this user key and the user's value (which will be > > the list of groups the user belongs to) > > > > ***** > > def groups_per_user(group_dictionary): > > user_groups = {} > > groups = [] > > # Go through group_dictionary > > for group,user in group_dictionary.items(): > > # Now go through the users in the group > > for user1 in user: > > groups.append(group) > > print(user1,groups) > > > > return(user_groups) > > > > print(groups_per_user({"local": ["admin", "userA"],"public": ["admin", > > "userB"],"administrator": ["admin"] })) > > > > ***** > > > This idea might be a bit more than you really want/are ready to try: > > The problem with inheriting from dict and list in Python > > https://treyhunner.com/2019/04/why-you-shouldnt-inherit-from-list-and-dict-… > > Although the article addresses a completely different set of interests, > the example used is class TwoWayDict( ... ) which implements a dict > having not only entries in the form key:value, but adds the > complementary?inverted value:key. > > He calls it "bi-directional": "When a key-value pair is added, the key > maps to the value but the value also maps to the key.". > > This is not *exactly* the spec in this post, in that Trey is using a > single dict, but there is absolutely no reason why the article's > solution(s) couldn't be extended so that the TwoWayDict class actually > manages two dicts - one key:value and the other value:key. > > This would then allow extension to the 1:m relationship*: > forward_dict ~ key1:value1,value2,value3 > inverted_dict ~ value1:key1,key2 > value2:key2,key5 > ... > > The philosophical difference in this approach lies in the *assembling* > of a data structure that it is prepared for future use/'ready for > action'; rather than using the algorithmic 'translation' currently > envisaged, in-between assembling the original dict, and being able to > make use of its inversion! > ie the complexity is in the 'writing' to the dict (or 'loading' it), > rather than in the 'reading' (or getting items from it)! > > OTOH understanding and coding the above will require some > reasonably-advanced Python knowledge and skills - hence the opening > questions! > > > * apologies if this term is unfamiliar: "one to many relationship", > refers to the idea that (here) one key may yield multiple values, cf > "one to one", eg your ID/SocialSecurityNR which can only apply to you > (and vice-versa). > > NB PSL's collections.UserDict stores its (single dict) keys and values > in a dict called "data" (IIRC). Thus adding a parallel, but reversed, > dict, eg "inverse" should be quite smooth to implement. > (YMMV ? famous last words) > -- > Regards =dn > > _______________________________________________ > Tutor maillist - Tutor(a)python.org > https://mail.python.org/mailman/listinfo/tutor >

3 2

Namespaces in Python
by Robert Alexander Jan. 30, 2020

Jan. 30, 2020

Not 100% sure this is appropriate, if not please correct me and won’t do it in the future but I thought some people on this list might like to know about a very well written Medium article on namespaces in Python: https://medium.com/better-programming/namespacing-with-python-79574d125564

1 0

Remove some known text around text I need to keep
by Robert Alexander Jan. 30, 2020

Jan. 30, 2020

Dear friends, I have 200 text files in which a doctor has “tagged” parts of the text as symptom, sign or therapy (in Italian SINTOMO, SEGNO, TERAPIA) as follows: [SEGNO: edemi declivi >> a sinistra] [SINTOMO: non lamenta dispnea] [SINTOMO: paziente sintomatica per dispnea moderata] [SEGNO: Non edemi] [SEGNO: calo di 2 kg (55,8 kg)] [TERAPIA: ha ridotto la terapia diuretica] [TERAPIA: Lieve riduzione della terapia diuretica] [TERAPIA: Lieve riduzione della terapia diuretica] and so forth. These lines can span over a single text line and I need to remove just the tags and rewrite the original text without them. To give you an example on the same lines as above what I need to write back in the new “clean” files are like the following: edemi declivi >> a sinistra] non lamenta dispnea] paziente sintomatica per dispnea moderata] Non edemi] calo di 2 kg (55,8 kg)] ha ridotto la terapia diuretica] Lieve riduzione della terapia diuretica] Lieve riduzione della terapia diuretica] if there was a newline in the text I should respect it and rewrite it out. I am not 100% sure about thehandling of the space between the tags (eg [SEGNO:) and the first word within it. What would you recommend? Regular expressions? Have a tutorial or document I can study? Thank you very much.

7 9

stalker-m3u.py
by Aleksa Jan. 29, 2020

Jan. 29, 2020

Error: Please upgrade your API plan to use filters or paging. NOT WORK..... Is there another way Thanks.. #!/usr/bin/env python # # stalker-m3u.py # Search SHODAN for Stalker Portal IPTV Servers M3U # # Author: random_robbie import shodan import sys import re import requests from time import sleep from requests.packages.urllib3.exceptions import InsecureRequestWarning requests.packages.urllib3.disable_warnings(InsecureRequestWarning) # Configuration API_KEY = "oCBoOofRgFReGU2ssMyp9Htqrfhgqlpf" SEARCH_FOR = 'title:"stalker_portal"' FILE = "/stalker_portal/server/tools/m3u.php" session = requests.Session() def grab_file (IP,PORT,FILE): print ("[*] Testing: "+IP+" on Port: "+PORT+"[*]\n") try: URL = "http://"+IP+":"+PORT+""+FILE+"" headers = {"User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:54.0) Gecko/20100101 Firefox/54.0"} response = session.get(URL, headers=headers, timeout=15, verify=False) result = response.text if '#EXTM3U' in result: text_file = open("./cfg/stalker-"+IP+".m3u8", "a") text_file.write(""+result+"") text_file.close() print ("[*] Stalker... Found [*]\n") else: print ("[*] Blocked [*]\n ") except KeyboardInterrupt: print ("Ctrl-c pressed ...") sys.exit(1) except Exception as e: print (e) print ("[*] Nothing Found on IP: "+IP+" [*]\n") try: # Setup the api api = shodan.Shodan(API_KEY) # Perform the search result = api.search(SEARCH_FOR) # Loop through the matches and print each IP for service in result['matches']: IP = service['ip_str'] PORT = str(service['port']) CC = service['location']['country_name'] grab_file (IP,PORT,FILE) except KeyboardInterrupt: print ("Ctrl-c pressed ...") sys.exit(1) except Exception as e: print('Error: %s' % e) sys.exit(1)

3 2

How to refactor a simple, straightforward script into a "proper" program?
by boB Stepp Jan. 29, 2020

Jan. 29, 2020

In a November thread I started, "How to type annotate complex dictionary containing lambdas?" (https://mail.python.org/pipermail/tutor/2019-November/115726.html), I justifiably received multiple critiques on what an awful dictionary I had created. Eventually I responded that the program that that dictionary was from (and other dictionaries like it) came from using what originally was a very simple script which over time became rather complex and gnarly from using it to try out different things I was learning about over time. At the time I started the aforementioned thread my learning topic of the day was type annotations, and, of course, I used my go to "simple" (Hah!) script to play around with that concept. So perhaps in line with D. L. Neil's "Friday Finking" series on the main Python list, I would like to start a discussion on how to properly transform a simple Python script into a battle-hardened program suitable for release to the general public. Below is my best reconstruction of what I probably originally wrote once upon a time: <version1.py => A simple throwaway script> ============================================================================ #!/usr/bin/env python3 """Calculate the number of pages per day needed to read a book by a given date.""" from datetime import date COUNT_TODAY = 1 num_pages_in_book = int(input("How many pages are there in your book? ")) num_pages_read = int(input("How many pages have you read? ")) today_date = date.today() goal_date = date.fromisoformat( input("What is your date to finish the book (yyyy-mm-dd)? ") ) days_to_goal = (goal_date - today_date).days pages_per_day = (num_pages_in_book - num_pages_read) / (days_to_goal + COUNT_TODAY) print( "\nYou must read", pages_per_day, "pages each day (starting today) to reach your goal.", ) ============================================================================ As this script is I believe it to be easy to read and understand by an outside reader. For my original purposes it quickly gave me what I wanted out of it. But if I wanted to "give it away" to the general public there are some things that bother me: 1) There is no error checking. If someone deliberately or mistakenly enters incorrect input the program will terminate with a ValueError exception. 2) There are no checks for logic errors. For instance, a person could enter a goal date that is prior to today or enter a date in the future that falls well beyond any human's possible lifespan (with current technology). 3) There is no formatting of output. It is possible to generate float output with many decimal places, something most users would not want to see. And does it make any sense to have non-integral numbers of pages anyway? 4) There are duplicated patterns of input in the code as is. Surely that duplication could be removed? 5) A minor, but bothersome quibble: If the reader need only read one page per day, the program would display an annoying "... 1.0 pages ...", which is grammatically incorrect. 6) There are no tests, which makes it more difficult to grow/maintain the program in the future. 7) The user must restart the program each time he/she wishes to try out different goal dates. 8) [Optional] There are no type annotations. So I am curious as to how you pros would approach the refactoring process. I think that such a demonstration would surely be educational for myself, and hopefully others. But I do realize that everyone does their thing voluntarily and my thoughts might not align with yours. So I am *hoping* a few experts go along with this, but, regardless, in typical boB fashion I will plow away and post my future efforts to transform version1.py into something more robust. Then those that wish to can critique version2.py leading ultimately to version-who-knows-what.py ... Anyway, it seems like a useful New Year's exercise that might actually be helpful. HAPPY NEW YEAR TO YOU AND YOURS!!! -- boB

8 21