🌐 Mailman 3 September 2023 - Tutor - python.org

Image processing
by Diana Katz Oct. 1, 2023

Oct. 1, 2023

Hi, My daughter has voltage data points from A homemade ultrasound that she is trying to convert into an ultrasound image. even a rudimentary picture. Is there any expert on here that can help us turning voltage signals into pixels? Knowledge of some high pass filtering too. Di k. Sent from my iPhone

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question about subroutine
by Emma Sweetland Sept. 30, 2023

Sept. 30, 2023

I was wondering if someone could advise about what is going wrong with this subroutine. With some debugging prints, I know the problem is definitely on line 9 when new[row][column] is assigned a new value. That part is working but the problem is that it is also changing the corresponding value in grid which is the list from which new was originally copied (using append). This is happening despite the fact that new and grid have different addresses (ids) so I don't understand how a change to new is affecting grid. Any help gratefully received. Thank you. Emma Sweetland Teacher - Mathematics E: ESweetland(a)bosworthcollege.com<mailto:ESweetland@bosworthcollege.com> W: www.bosworthcollege.com<https://www.bosworthcollege.com/> M: T: +44 1604 239 995 [cid:c69baae0-d942-4dfa-b7be-09ed03472196] [cid:637d5568-d010-4e8d-9756-004cd338ad23] [cid:6374fa7e-d9ca-4eaf-bf20-d9e56505b5fd]<https://www.facebook.com/BosworthCollege/> [cid:857bfdde-db53-4e9d-8a20-9ca86c9a9b21]<https://www.instagram.com/bosworthindependentcollege/?hl=en> [cid:b198bc7c-c119-47a3-849f-8999861a6ba2]<https://www.youtube.com/user/BosworthIndepCollege> This e-mail and any files transmitted with it are confidential and intended solely for the use of the individual or entity to whom they are addressed. If you have received this e-mail in error please notify the originator of the message. Any views expressed in this message are those of the individual sender, except where the sender specifies and with authority, states them to be the views of Bright Scholar (UK) Holdings Limited, trading as CATS Global Schools and/or subsidiary companies. In order to prevent fraudulent activity (including phishing), we will not request you to pay any invoices or monies into accounts other than the account stated within its own invoice(s). Any change to such accounts will be an exceptional occurrence and any such request, purported to be from us, should be subject to your own additional authentication or verification steps prior to making any such change or payment(s). This message has been scanned for malware by Office 365. www.office365.com

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re code
by Verizon!! Sept. 30, 2023

Sept. 30, 2023

I have a program coded in visual basic 6.0 and want to code it in python. I'm in Pompano Beach Florida and hoping that a python guru is close by. The program takes a comma delimited data file with 1400+ fields and pulls out specific fields applies some calcs and formulas and outputs a report

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Re my Tkinter question - problem solved
by Phil Sept. 30, 2023

Sept. 30, 2023

I hope this is caught before my previous question passes the moderation test. -- Regards, Phil

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Tkinter button command question
by Phil Sept. 29, 2023

Sept. 29, 2023

This is a confusing problem so I'll do my best to explain it clearly. I have created a Tkinter app that consists of two classes; an App and an Entry class. The entry class has a variable named self.a and is set like this: self.a = "". Each class has an identical function named solve(). The Entry class has a button defined as follows: solve_button = customtkinter.CTkButton( self, text="solve", width=80, #command=self.solve, command=self.master.solve, # This calls the App class solve function ) If the command calls the Entry class solve() then self.a = "x" (self.a is set to "x" before the solve button is pressed). If the command calls the App class solve then self.a = "", the initial value of self.a. I hope that someone can offer a working suggestion because I've reached the limit of my ability. By the way, my AI friend suggested "command=self.master.solve" but cannot offer a working solution that solves the problem. self.a = "x" when command=self.solve and self.x = "" when command=self.master.solve. I should mention that I have stepped through the code with the debugger and the App class solve() is called after the button is pressed and after self.a is set to "x". -- Regards, Phil

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wordcount.py provided exercise solution not working?
by Matthew Borkenhagen Sept. 21, 2023

Sept. 21, 2023

Hello, In working through Google's Python Class ( https://developers.google.com/edu/python) I just ran the provided solution from Google for the exercise on dicts and files: wordcount.py When I run this program while in the proper directory at the command prompt, the program only prints *this result*: *usage: ./wordcount.py {--count | --topcount} file* My question is this--Is this provided solution ever reading a file? (What is the filename that it should be reading called? Where would this file be located? In the directory google-python-exercises\basic\solution or would I need to create a file myself for it to read in order to test the program?) I have copied and pasted the provided solution for this exercise below. Thanks, Matt Borkenhagen #!/usr/bin/python3 # Copyright 2010 Google Inc. # Licensed under the Apache License, Version 2.0 # http://www.apache.org/licenses/LICENSE-2.0 # Google's Python Class # http://code.google.com/edu/languages/google-python-class/ """Wordcount exercise Google's Python class The main() below is already defined and complete. It calls print_words() and print_top() functions which you write. 1. For the --count flag, implement a print_words(filename) function that counts how often each word appears in the text and prints: word1 count1 word2 count2 ... Print the above list in order sorted by word (python will sort punctuation to come before letters -- that's fine). Store all the words as lowercase, so 'The' and 'the' count as the same word. 2. For the --topcount flag, implement a print_top(filename) which is similar to print_words() but which prints just the top 20 most common words sorted so the most common word is first, then the next most common, and so on. Use str.split() (no arguments) to split on all whitespace. Workflow: don't build the whole program at once. Get it to an intermediate milestone and print your data structure and sys.exit(0). When that's working, try for the next milestone. Optional: define a helper function to avoid code duplication inside print_words() and print_top(). """ import sys # +++your code here+++ # Define print_words(filename) and print_top(filename) functions. # You could write a helper utility function that reads a file # and builds and returns a word/count dict for it. # Then print_words() and print_top() can just call the utility function. #### LAB(begin solution) def word_count_dict(filename): """Returns a word/count dict for this filename.""" # Utility used by count() and Topcount(). word_count = {} # Map each word to its count input_file = open(filename, encoding='utf-8') for line in input_file: words = line.split() for word in words: word = word.lower() # Special case if we're seeing this word for the first time. if not word in word_count: word_count[word] = 1 else: word_count[word] = word_count[word] + 1 input_file.close() # Not strictly required, but good form. return word_count def print_words(filename): """Prints one per line '<word> <count>' sorted by word for the given file.""" word_count = word_count_dict(filename) words = sorted(word_count.keys()) for word in words: print(word, word_count[word]) def get_count(word_count_tuple): """Returns the count from a dict word/count tuple -- used for custom sort.""" return word_count_tuple[1] def print_top(filename): """Prints the top count listing for the given file.""" word_count = word_count_dict(filename) # Each item is a (word, count) tuple. # Sort them so the big counts are first using key=get_count() to extract count. items = sorted(word_count.items(), key=get_count, reverse=True) # Print the first 20 for item in items[:20]: print(item[0], item[1]) ##### LAB(end solution) # This basic command line argument parsing code is provided and # calls the print_words() and print_top() functions which you must define. def main(): if len(sys.argv) != 3: print('usage: ./wordcount.py {--count | --topcount} file') sys.exit(1) option = sys.argv[1] filename = sys.argv[2] if option == '--count': print_words(filename) elif option == '--topcount': print_top(filename) else: print('unknown option: ' + option) sys.exit(1) if __name__ == '__main__': main()

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Fwd: im having problems and need help
by Leam Hall Sept. 20, 2023

Sept. 20, 2023

Hey Robert, no worries! If I am using whole numbers for division, like 3, and 20, then: 20 divided by 3 gives 6. 3 times 6 is 18, and if I am dividing into 20, there is 2 left over. So, 20 % 3 is 2, since there is 2 left over. When you say: if number % 2 == 0: You have already proven that the number is even. Does that help? Leam -------- Forwarded Message -------- Subject: Re: [Tutor] im having problems and need help Date: Wed, 20 Sep 2023 12:03:12 -0700 From: Robert Towne <townerobert1(a)gmail.com> To: Leam Hall <leamhall(a)gmail.com> I'm lost on the modelo. % it's a reminder? I don't understand it. I ran it in print(number%2). No matter what the number was it would come out to 1 or 0. I'm thinking the % is like a pre program. If it's even or odd. I'm not sure. Though. I'm stuck. I can run a while loop. But I'm lost at this modulo %. On Wed, Sep 20, 2023, 4:48 AM Leam Hall <leamhall(a)gmail.com <mailto:leamhall@gmail.com>> wrote: Robert, Sorry, your mail program killed the code indents. Also, "%" is the modulus/modulo operator, not the power. >>> 20 % 2 0 So, the while line: number % 2 == 0 Returns True if number is even. It says "If number / 2 leaves no remainder". Compare that to: >>> 20 % 3 2 Which says "20 / 3 leaves a remainder of 2". Hope that helps. Leam On 9/15/23 15:07, Robert Towne wrote: > Im having problems understanding this. Im running the while loop like it > says; and it doesnt complete the loop. > My question is, is it the formula thats wrong or my math. The % sign means > to square the number? > since i the to the second power is 64. Then it should return false. IDK > what I am doing wrong, if you could > help me understand where I am going wrong i would appreciate it thank you. > > def is_power_of_two(number): > # This while loop checks if the "number" can be divided by two > # without leaving a remainder. How can you change the while loop to > # avoid a Python ZeroDivisionError? > while number % 2 == 0: > number = number / 2 > # If after dividing by 2 "number" equals 1, then "number" is a power > # of 2. > if number == 1: > return True > return False > > # Calls to the function > print(is_power_of_two(0)) # Should be False > print(is_power_of_two(1)) # Should be True > print(is_power_of_two(8)) # Should be True > print(is_power_of_two(9)) # Should be False > _______________________________________________ > Tutor maillist - Tutor(a)python.org <mailto:Tutor@python.org> > To unsubscribe or change subscription options: > https://mail.python.org/mailman/listinfo/tutor <https://mail.python.org/mailman/listinfo/tutor> -- Software Engineer (reuel.net/resume <http://reuel.net/resume>) Scribe: The Domici War (domiciwar.net <http://domiciwar.net>) General Ne'er-do-well (github.com/LeamHall <http://github.com/LeamHall>) _______________________________________________ Tutor maillist - Tutor(a)python.org <mailto:Tutor@python.org> To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor <https://mail.python.org/mailman/listinfo/tutor> -- Software Engineer (reuel.net/resume) Scribe: The Domici War (domiciwar.net) General Ne'er-do-well (github.com/LeamHall)

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Keep getting error message when importing file saved to Jupyter
by Ashley Mungo Sept. 20, 2023

Sept. 20, 2023

[image: image.png] Hey Team, I keep getting the above message when I try to load a folder that is saved in Jupyter. I have already taken it out of read-only and updated the permissions but it still won't allow me to upload the folder. Help please!

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im having problems and need help
by Robert Towne Sept. 20, 2023

Sept. 20, 2023

Im having problems understanding this. Im running the while loop like it says; and it doesnt complete the loop. My question is, is it the formula thats wrong or my math. The % sign means to square the number? since i the to the second power is 64. Then it should return false. IDK what I am doing wrong, if you could help me understand where I am going wrong i would appreciate it thank you. def is_power_of_two(number): # This while loop checks if the "number" can be divided by two # without leaving a remainder. How can you change the while loop to # avoid a Python ZeroDivisionError? while number % 2 == 0: number = number / 2 # If after dividing by 2 "number" equals 1, then "number" is a power # of 2. if number == 1: return True return False # Calls to the function print(is_power_of_two(0)) # Should be False print(is_power_of_two(1)) # Should be True print(is_power_of_two(8)) # Should be True print(is_power_of_two(9)) # Should be False

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ANN: Wed 20 Sep: Terminal-based user interfaces (TUIs) with ease using Textual
by dn Sept. 7, 2023

Sept. 7, 2023

Rodrigo's back! Fresh from his successes at EuroPython... You are invited to join the next virtual NZPUG Auckland Branch meeting (Wed 20 Sep, 1830~2030 local, ie 0630~0830 UTC) Learn how to build powerful terminal-based user interfaces (TUIs) with ease using Textual - an open-source Python framework. Through this tutorial, you'll learn how to use features like Textual's built-in widgets, reactive attributes, and message-passing system, to start developing a simple TODO app that runs directly in your terminal. About Rodrigo Girão Serrão: Rodrigo has presented to NZPUG Auckland Branch previously. He speaks frequently at various PyCons (Python Conferences) and other gatherings. As well as Python, he has been playing with APL, C++, and more. Combining programming and maths, he describes himself as a mathemagician. Rodrigo has always been fascinated by problem solving and that is why he picked up programming – so that he could solve more problems. He also loves sharing knowledge, and that is why he spends so much time writing articles in his blog, writing on Twitter, and giving workshops and courses. During the week, Rodrigo can be found banging his head against the wall while trying to solve a Textual bug, as he works on Textual full-time. To RSVP (to receive the meeting-URL) and for more detail: https://www.meetup.com/nzpug-auckland/events/295433884/ The Auckland branch of the New Zealand Python Users Group meets twice monthly. You're very welcome to attend online or in-person (as available). Meeting location-details or URL will be sent to those who RSVP. We are a healthy mix of Python users. Students, academics, hobbyists, industry professionals, and many completely new to Python. The 'room' opens at 1815 (local time) with an opportunity to network with colleagues. Formal start is 1830. Aiming to finish by 2030. We are always keen to hear suggestions for meeting-topics, and to meet with folk who'd like to present or lead - eg a brief lightning talk, a practical coaching-session, a full lecture... Help is available if you've never done such a thing before! We follow the NZPUG Code of Conduct to create an inclusive and friendly environment. We express thanks to, and encourage you to investigate our sponsors: Catalyst Cloud, New Zealand Open Source Society, JetBrains, and IceHouse Ventures. -- Regards, =dn

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