fiedler#
- scipy.linalg.fiedler(a)[source]#
Returns a symmetric Fiedler matrix
Given an sequence of numbers a, Fiedler matrices have the structure
F[i, j] = np.abs(a[i] - a[j])
, and hence zero diagonals and nonnegative entries. A Fiedler matrix has a dominant positive eigenvalue and other eigenvalues are negative. Although not valid generally, for certain inputs, the inverse and the determinant can be derived explicitly as given in [1].- Parameters:
- a(β¦, n,) array_like
Coefficient array. N-dimensional arrays are treated as a batch: each slice along the last axis is a 1-D coefficient array.
- Returns:
- F(β¦, n, n) ndarray
Fiedler matrix. For batch input, each slice of shape
(n, n)
along the last two dimensions of the output corresponds with a slice of shape(n,)
along the last dimension of the input.
Notes
Added in version 1.3.0.
Array API Standard Support
fiedler
has experimental support for Python Array API Standard compatible backends in addition to NumPy. Please consider testing these features by setting an environment variableSCIPY_ARRAY_API=1
and providing CuPy, PyTorch, JAX, or Dask arrays as array arguments. The following combinations of backend and device (or other capability) are supported.Library
CPU
GPU
NumPy
β
n/a
CuPy
n/a
β
PyTorch
β
β
JAX
β
β
Dask
β
n/a
See Support for the array API standard for more information.
References
[1]J. Todd, βBasic Numerical Mathematics: Vol.2 : Numerical Algebraβ, 1977, Birkhauser, DOI:10.1007/978-3-0348-7286-7
Examples
>>> import numpy as np >>> from scipy.linalg import det, inv, fiedler >>> a = [1, 4, 12, 45, 77] >>> n = len(a) >>> A = fiedler(a) >>> A array([[ 0, 3, 11, 44, 76], [ 3, 0, 8, 41, 73], [11, 8, 0, 33, 65], [44, 41, 33, 0, 32], [76, 73, 65, 32, 0]])
The explicit formulas for determinant and inverse seem to hold only for monotonically increasing/decreasing arrays. Note the tridiagonal structure and the corners.
>>> Ai = inv(A) >>> Ai[np.abs(Ai) < 1e-12] = 0. # cleanup the numerical noise for display >>> Ai array([[-0.16008772, 0.16666667, 0. , 0. , 0.00657895], [ 0.16666667, -0.22916667, 0.0625 , 0. , 0. ], [ 0. , 0.0625 , -0.07765152, 0.01515152, 0. ], [ 0. , 0. , 0.01515152, -0.03077652, 0.015625 ], [ 0.00657895, 0. , 0. , 0.015625 , -0.00904605]]) >>> det(A) 15409151.999999998 >>> (-1)**(n-1) * 2**(n-2) * np.diff(a).prod() * (a[-1] - a[0]) 15409152