C++ Program to Copy the Contents of One Array Into Another in the Reverse Order
Last Updated :
23 Jul, 2025
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Given an array, the task is to copy these array elements into another array in reverse array.
Examples:
Input: array: 1 2 3 4 5 Output: 5 4 3 2 1 Input: array: 10 20 30 40 50 Output: 50 40 30 20 10
Let len be the length of original array. We copy every element original_arr[i] to copy_arr[n-i-1] to get reverse in copy_arr[].
// C program to copy the contents
// of one array into another
// in the reverse order
#include <stdio.h>
// Function to print the array
void printArray(int arr[], int len)
{
int i;
for (i = 0; i < len; i++) {
printf("%d ", arr[i]);
}
}
// Driver code
int main()
{
int original_arr[] = {1, 2, 3, 4, 5};
int len = sizeof(original_arr)/sizeof(original_arr[0]);
int copied_arr[len], i, j;
// Copy the elements of the array
// in the copied_arr in Reverse Order
for (i = 0; i < len; i++) {
copied_arr[i] = original_arr[len - i - 1];
}
// Print the original_arr
printf("
Original array: ");
printArray(original_arr, len);
// Print the copied array
printf("
Resultant array: ");
printArray(copied_arr, len);
return 0;
}
Output:
Original array: 1 2 3 4 5 Resultant array: 5 4 3 2 1
Time Complexity: O(len)
Auxiliary Space: O(len)
