C program to create copy of a singly Linked List using Recursion
Given a pointer to the head node of a Linked List, the task is to create a copy of the linked list using recursion.
Examples::
Input: Head of following linked list
1->2->3->4->NULL
Output:
Original list: 1 -> 2 -> 3 -> 4 -> NULL
Duplicate list: 1 -> 2 -> 3 -> 4 -> NULLInput: Head of following linked list
1->2->3->4->5->NULL
Output:
Original list: 1->2->3->4->5->NULL,
Duplicate list: 1->2->3->4->5->NULL,
Approach: Follow the steps below to solve the problem:
- Base case: if (head == NULL), then return NULL.
- Allocate the new Node in the Heap using malloc() & set its data.
- Recursively set the next pointer of the new Node by recurring for the remaining nodes.
- Return the head pointer of the duplicate node.
- Finally, print both the original linked list and the duplicate linked list.
Below is the implementation of the above approach:
// C program for the above approach
#include <stdio.h>
#include <stdlib.h>
// Node for linked list
struct Node {
int data;
struct Node* next;
};
// Function to print given linked list
void printList(struct Node* head)
{
struct Node* ptr = head;
while (ptr) {
printf("%d -> ", ptr->data);
ptr = ptr->next;
}
printf("NULL");
}
// Function to create a new node
void insert(struct Node** head_ref, int data)
{
// Allocate the memory for new Node
// in the heap and set its data
struct Node* newNode
= (struct Node*)malloc(
sizeof(struct Node));
newNode->data = data;
// Set the next node pointer of the
// new Node to point to the current
// node of the list
newNode->next = *head_ref;
// Change the pointer of head to point
// to the new Node
*head_ref = newNode;
}
// Function to create a copy of a linked list
struct Node* copyList(struct Node* head)
{
if (head == NULL) {
return NULL;
}
else {
// Allocate the memory for new Node
// in the heap and set its data
struct Node* newNode
= (struct Node*)malloc(
sizeof(struct Node));
newNode->data = head->data;
// Recursively set the next pointer of
// the new Node by recurring for the
// remaining nodes
newNode->next = copyList(head->next);
return newNode;
}
}
// Function to create the new linked list
struct Node* create(int arr[], int N)
{
// Pointer to point the head node
// of the singly linked list
struct Node* head_ref = NULL;
// Construct the linked list
for (int i = N - 1; i >= 0; i--) {
insert(&head_ref, arr[i]);
}
// Return the head pointer
return head_ref;
}
// Function to create both the lists
void printLists(struct Node* head_ref,
struct Node* dup)
{
printf("Original list: ");
// Print the original linked list
printList(head_ref);
printf("\nDuplicate list: ");
// Print the duplicate linked list
printList(dup);
}
// Driver Code
int main(void)
{
// Given nodes value
int arr[] = { 1, 2, 3, 4, 5 };
int N = sizeof(arr) / sizeof(arr[0]);
// Head of the original Linked list
struct Node* head_ref = create(arr, N);
// Head of the duplicate Linked List
struct Node* dup = copyList(head_ref);
printLists(head_ref, dup);
return 0;
}
Original list: 1 -> 2 -> 3 -> 4 -> 5 -> NULL Duplicate list: 1 -> 2 -> 3 -> 4 -> 5 -> NULL
Time Complexity: O(N)
Auxiliary Space: O(N)