numpy.less() in Python
Last Updated :
08 Mar, 2024
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The numpy.less() : checks whether x1 is lesser than x2 or not. Syntax :
numpy.less(x1, x2[, out])
Parameters :
x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be
broadcastable to a common shape
out : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.
Return :
Boolean array indicating results, whether x1 is lesser than x2 or not.
Code 1 :
# Python Program illustrating
# numpy.less() method
import numpy as geek
a = geek.less([8., 2.], [5., 3.])
print("Not equal : \n", a, "\n")
b = geek.less([2, 2], [[1, 3],[1, 4]])
print("Not equal : \n", b, "\n")
a = geek.array([4,2])
b = geek.array([6,2])
print("Is a lesser than b : ", a < b)
Output :
Not equal : [False True] Not equal : [[False True] [False True]] Is a lesser than b : [ True False]]
Code 2 :
# Python Program illustrating
# numpy.less() method
import numpy as geek
# Here we will compare Complex values with int
a = geek.array([1j,2])
b = geek.array([1,2])
# indicating 1j is lesser than 1
print("Comparing complex with int : ", a < b)
# indicating 1j is lesser than 1
d = geek.less(a, b)
print("\n Comparing complex with int .less() : ", d)
Output :
Comparing complex with int : [ True False] Comparing complex with int .less() : [ True False]
Code 3 :
# Python Program illustrating
# numpy.less() method
import numpy as geek
# Here we will compare Float with int values
a = geek.array([1.1, 1])
b = geek.array([1, 2])
# indicating 1.1 is greater than 1
print("Comparing float with int : ", a < b)
# indicating 1.1 is greater than 1
d = geek.less(a, b)
print("\n Comparing float with int using .less() : ", d)
Output :
Comparing float with int : [False True] Comparing float with int using .less() : [False True]
