Class Solution
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- All Implemented Interfaces:
public final class Solution
832 - Flipping an Image.
Easy
Given an
n x n
binary matriximage
, flip the image horizontally , then invert it, and return the resulting image.To flip an image horizontally means that each row of the image is reversed.
For example, flipping
[1,1,0]
horizontally results in[0,1,1]
.
To invert an image means that each
0
is replaced by1
, and each1
is replaced by0
.For example, inverting
[0,1,1]
results in[1,0,0]
.
Example 1:
Input: image = \[\[1,1,0],1,0,1,0,0,0]
Output: \[\[1,0,0],0,1,0,1,1,1]
Explanation: First reverse each row: \[\[0,1,1],1,0,1,0,0,0]. Then, invert the image: \[\[1,0,0],0,1,0,1,1,1]
Example 2:
Input: image = \[\[1,1,0,0],1,0,0,1,0,1,1,1,1,0,1,0]
Output: \[\[1,1,0,0],0,1,1,0,0,0,0,1,1,0,1,0]
Explanation: First reverse each row: \[\[0,0,1,1],1,0,0,1,1,1,1,0,0,1,0,1]. Then invert the image: \[\[1,1,0,0],0,1,1,0,0,0,0,1,1,0,1,0]
Constraints:
n == image.length
n == image[i].length
1 <= n <= 20
images[i][j]
is either0
or1
.
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Method Detail
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flipAndInvertImage
final Array<IntArray> flipAndInvertImage(Array<IntArray> image)
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