🌐 Mailman 3 September 2016 - Python-list - python.org

Re: How to get the source code of python function being decorated?
by Ned Batchelder Sept. 16, 2016

Sept. 16, 2016

On Friday, September 16, 2016 at 3:20:15 PM UTC-4, Peng Yu wrote: > Hi, See the following example, I am not able to get the source code of > the actual function that does the calculation of partial_ratio. Does > anybody know what is the correct way of getting the source? > > /tmp$ ./main.py > @functools.wraps(func) > def decorator(*args, **kwargs): > if args[0] is None or args[1] is None: > return 0 > return func(*args, **kwargs) > > /tmp$ cat ./main.py > #!/usr/bin/env python > # vim: set noexpandtab tabstop=2 shiftwidth=2 softtabstop=-1 fileencoding=utf-8: > > import fuzzywuzzy.fuzz > import inspect > print inspect.getsource(fuzzywuzzy.fuzz.partial_ratio) > In general, you can't get at the decorated function. Decorators can do anything they want with the function they decorate, including completely ignore it, or store it in a closure, assign it to a global, add it to a data structure, etc. Can you tell us more about the problem you are trying to solve? Why do you want a program that access the source of decorated functions? Maybe there's another way to get at what you need. --Ned.

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why this code loop forever after a draw a rectangle
by meInvent bbird Sept. 16, 2016

Sept. 16, 2016

im = img.copy() cntcounter = 0 for cnt in contours: epsilon = 0.1*cv2.arcLength(cnt,True) approx = cv2.approxPolyDP(cnt,epsilon,True) #peri = cv2.arcLength(cnt, True) #approx = cv2.approxPolyDP(c, 0.5 * peri, True) #print("len(approx)="+str(len(approx))) if len(approx) == 4: print("approx=" + str(approx)) cntcounter = cntcounter + 1 print("here1") x,y,w,h = cv2.boundingRect(cnt) print("here2") while im is None: time.sleep(1) if im is not None: print("here3") im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2) #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2) #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2) #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2) #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2) cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)

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Re: why this code loop forever after a draw a rectangle
by meInvent bbird Sept. 16, 2016

Sept. 16, 2016

i follow this post to give some time it to operate, wait a long time still looping http://answers.opencv.org/question/60094/libpng-warning-image-width-is-zero… i can not stand this Ninja coding life any more, i have to open my code for ask this error import cv2 import numpy as np #from matplotlib import pyplot as plt import time #print("1=" + str(int(sys.argv[1]))) #print("2=" + str(int(sys.argv[2]))) #print("3=" + str(int(sys.argv[3]))) img_rgb = cv2.imread(r'C:\Users\martin\Documents\scree2.png') img_gray = cv2.cvtColor(img_rgb, cv2.COLOR_BGR2GRAY) template = cv2.imread(r'C:\Users\martin\Documents\dragob.png',0) w, h = template.shape[::-1] res = cv2.matchTemplate(img_gray,template,cv2.TM_CCOEFF_NORMED) threshold = 0.64 loc = np.where( res >= threshold) pt = [(0,0)] while not zip(*loc[::-1]): threshold = threshold - 0.02 loc = np.where( res >= threshold) counter = 1 print("threshold="+str(threshold)) for pt2 in zip(*loc[::-1]): cv2.rectangle(img_rgb, pt2, (pt2[0] + w, pt2[1] + h), (0,0,255), 2) pt = pt2 crop_img = img_rgb[pt[1]:(pt[1]+h), pt[0]:(pt[0]+w)] counter = counter + 1 cv2.imwrite("C:\\Users\\tester\\Documents\\res.png",crop_img) #import cv2 #winName = "Movement Indicator" #cv2.namedWindow(winName, cv2.WINDOW_NORMAL) img = cv2.imread(r'C:\Users\tester\Documents\res.png',1) gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY) height, width = gray.shape edges = cv2.Canny(gray,height,width,apertureSize = 3) #edges = cv2.Canny(gray,30,200) #gray = cv2.cvtColor(img, cv2.COLOR_RGB2GRAY) #ret,thresh = cv2.threshold(edges.copy(),cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE,0) ret,thresh = cv2.threshold(edges,250,150,0) contours,hierarchy = cv2.findContours(thresh, 1, 2) #contours = sorted(contours, key = cv2.contourArea, reverse = True)[:10] im = img.copy() cntcounter = 0 for cnt in contours: epsilon = 0.1*cv2.arcLength(cnt,True) approx = cv2.approxPolyDP(cnt,epsilon,True) #peri = cv2.arcLength(cnt, True) #approx = cv2.approxPolyDP(c, 0.5 * peri, True) #print("len(approx)="+str(len(approx))) if len(approx) == 4: print("approx=" + str(approx)) cntcounter = cntcounter + 1 print("here1") x,y,w,h = cv2.boundingRect(cnt) print("here2") #im = img.copy() while im is None: time.sleep(1) if im is not None: print("here3") im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2) #cv2.imwrite("C:\\Users\\martin\\Documents\\masda"+str(cntcounter)+".png",imi) #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2) #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2) #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2) #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2) On Friday, September 16, 2016 at 7:34:04 PM UTC+8, Waffle wrote: > On 16 September 2016 at 14:24, meInvent bbird <jobmattcon(a)gmail.com> wrote: > > im = img.copy() > > cntcounter = 0 > > for cnt in contours: > > epsilon = 0.1*cv2.arcLength(cnt,True) > > approx = cv2.approxPolyDP(cnt,epsilon,True) > > #peri = cv2.arcLength(cnt, True) > > #approx = cv2.approxPolyDP(c, 0.5 * peri, True) > > #print("len(approx)="+str(len(approx))) > > if len(approx) == 4: > > print("approx=" + str(approx)) > > cntcounter = cntcounter + 1 > > print("here1") > > x,y,w,h = cv2.boundingRect(cnt) > > print("here2") > > while im is None: > > time.sleep(1) > > if im is not None: > > print("here3") > > im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2) > > #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2) > > #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2) > > #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2) > > #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2) > > > > > > cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im) > > -- > > https://mail.python.org/mailman/listinfo/python-list > > not sure but.. this bit reads really suspicious: > > while im is None: > time.sleep(1) > > if im is ever None then how will it ever become not None? unless there > is some other thread at work i can't really see this happening. > and if there is some other thread at work then there is probably some > better solution than sleep()

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Re: how to automate java application in window using python
by meInvent bbird Sept. 16, 2016

Sept. 16, 2016

On Friday, September 16, 2016 at 2:26:47 AM UTC+8, bream...(a)gmail.com wrote: > On Thursday, September 15, 2016 at 8:13:05 AM UTC+1, meInvent bbird wrote: > > how to automate java application in window using python > > > > 1. scroll up or down of scroll bar > > 2. click button > > 3. type text in textbox > > Please read this http://www.catb.org/esr/faqs/smart-questions.html and then this http://sscce.org/ and then rephrase your post. > > Kindest regards. > > Mark Lawrence. i find this, but it is not python, it is a product http://sqa.stackexchange.com/questions/18134/python-based-test-automation-t…

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Find Nested group in LDAP by this i mean group in group
by Robert Clove Sept. 16, 2016

Sept. 16, 2016

Hi, I was looking for search query in LDAP for nested group memebership. It would be great if someone can provide the python code for the same. Regards

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Expected type 'optional[bytes]' got 'str' instead
by Daiyue Weng Sept. 16, 2016

Sept. 16, 2016

Hi, I have the following piece of code, rootPath = os.path.abspath(__file__) rootPath = (rootPath.rsplit('\\', 1)[0]).rsplit('\\', 1)[0] PyCharm inspection gave me warning on argument '\\' of the 2nd rsplit, Expected type 'optional[bytes]' got 'str' instead If I changed it to, rootPath = (rootPath.rsplit('\\', 1)[0]).rsplit(b'\\', 1)[0] Python game me errors, TypeError: Can't convert 'bytes' object to str implicitly How to fix it? cheers

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Re: Requests for webbrowser module
by John Gordon Sept. 16, 2016

Sept. 16, 2016

In <mailman.196.1473872323.2411.python-list(a)python.org> Jamie <ja9749(a)my.bristol.ac.uk> writes: > I am not sure if this is an intended consequence but when using the > webbrowser module to open a new blank browser tab in chrome it opens it > in a new browser window instead of using the current window. Providing There is an internal setting within Chrome that controls whether new pages are opened in a new tab or a new window. Perhaps that is your issue? -- John Gordon A is for Amy, who fell down the stairs gordon(a)panix.com B is for Basil, assaulted by bears -- Edward Gorey, "The Gashlycrumb Tinies"

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how to robot recognize basic geometric object in window or ubuntu window
by meInvent bbird Sept. 15, 2016

Sept. 15, 2016

i am doing a robot to automate window itself with python i give some basic png diagram such as square, circle, triangle and hope it recognize all kinds of square like things in window such as textbox of notepad etc how a robot recognize basic geometric object in window or ubuntu window i use cv2 template matching method and then draw black square or rectangle as a template however, it can recognize the size of template only and recognize not a square diagram from capture screen then i try a black ground and white line of square, it recognize a File in menu i feel that it need to try all kinds of color, and size in order to recognize similar object in screen capture diagram how do a robot recognize many color and size in seconds?

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Re: Oh gods can we get any more off-topic *wink* [was Re: [Python-ideas] Inconsistencies]
by Marko Rauhamaa Sept. 15, 2016

Sept. 15, 2016

Random832 <random832(a)fastmail.com>: > On Thu, Sep 15, 2016, at 15:06, Steve D'Aprano wrote: >> No, the horizon would still be horizontal. It merely wouldn't *look* >> horizontal, an optical illusion. > > I guess that depends on your definition of what a horizon is - and > what a straight line is, if not the path followed by a beam of light. It is actually quite interesting how the brain forms an accurate idea of a straight line and, say, a circle. Whenever you get a new pair of glasses, the brain needs a recalibration and manages to do it within a week. I don't think it has anything with "the path followed by a beam of light." Marko

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Re: Oh gods can we get any more off-topic *wink* [was Re: [Python-ideas] Inconsistencies]
by Steve D'Aprano Sept. 15, 2016

Sept. 15, 2016

On Fri, 16 Sep 2016 05:19 am, Random832 wrote: > On Thu, Sep 15, 2016, at 15:06, Steve D'Aprano wrote: >> No, the horizon would still be horizontal. It merely wouldn't *look* >> horizontal, an optical illusion. > > I guess that depends on your definition of what a horizon is - and what > a straight line is, if not the path followed by a beam of light. Light follows geodesics, not straight lines. http://mathworld.wolfram.com/Geodesic.html Hmmm... actually that suggests that an infinite flat earth is *not* a Newtonian black hole, as I suggested, since light in Newtonian physics travels in straight lines. So it would be an unusual kind of relativistic black hole. (A Newtonian black hole is just a star or planet sufficiently big that the escape velocity is greater than the speed of light. Hmmm again... what is the escape velocity of an infinite plane with gravitational acceleration of 1 gee?) -- Steve “Cheer up,” they said, “things could be worse.” So I cheered up, and sure enough, things got worse.

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