MySQL GROUP BY Statement
The MySQL GROUP BY Statement
The GROUP BY statement groups rows that have the same values into summary
rows, like "find the number of customers in each country".
The GROUP BY statement is often used with aggregate functions (COUNT(),
MAX(),
MIN(), SUM(),
AVG()) to group the result-set by one or more columns.
GROUP BY Syntax
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
ORDER BY column_name(s);
Demo Database
Below is a selection from the "Customers" table in the Northwind sample database:
| CustomerID | CustomerName | ContactName | Address | City | PostalCode | Country |
|---|---|---|---|---|---|---|
| 1 |
Alfreds Futterkiste | Maria Anders | Obere Str. 57 | Berlin | 12209 | Germany |
| 2 | Ana Trujillo Emparedados y helados | Ana Trujillo | Avda. de la Constituciรณn 2222 | Mรฉxico D.F. | 05021 | Mexico |
| 3 | Antonio Moreno Taquerรญa | Antonio Moreno | Mataderos 2312 | Mรฉxico D.F. | 05023 | Mexico |
| 4 |
Around the Horn | Thomas Hardy | 120 Hanover Sq. | London | WA1 1DP | UK |
| 5 | Berglunds snabbkรถp | Christina Berglund | Berguvsvรคgen 8 | Luleรฅ | S-958 22 | Sweden |
MySQL GROUP BY Examples
The following SQL statement lists the number of customers in each country:
The following SQL statement lists the number of customers in each country, sorted high to low:
Example
SELECT COUNT(CustomerID), Country
FROM Customers
GROUP BY Country
ORDER BY COUNT(CustomerID) DESC;
Try it Yourself ยป
Demo Database
Below is a selection from the "Orders" table in the Northwind sample database:
| OrderID | CustomerID | EmployeeID | OrderDate | ShipperID |
|---|---|---|---|---|
| 10248 | 90 | 5 | 1996-07-04 | 3 |
| 10249 | 81 | 6 | 1996-07-05 | 1 |
| 10250 | 34 | 4 | 1996-07-08 | 2 |
And a selection from the "Shippers" table:
| ShipperID | ShipperName |
|---|---|
| 1 | Speedy Express |
| 2 | United Package |
| 3 | Federal Shipping |
GROUP BY With JOIN Example
The following SQL statement lists the number of orders sent by each shipper:
Example
SELECT Shippers.ShipperName, COUNT(Orders.OrderID) AS NumberOfOrders FROM
Orders
LEFT JOIN Shippers ON Orders.ShipperID = Shippers.ShipperID
GROUP BY ShipperName;
Try it Yourself ยป
